NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

# NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

## NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 are the part of NCERT Solutions for Class 6 Maths. Here you can find the NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3.

### Ex 6.3 Class 6 Maths Question 1.

Find:
(a) 35 – (20)
(b) 72 – (90)
(c) (-15) – (-18)
(d) (-20) – (13)
(e) 23 – (-12)
(f) (-32) – (-40)

Solution:
(a) 35 – (20) = 35 – 20 = 15

(b) 72 – 90 = –18

(c) (-15) – (-18) = -15 + 18 = 3

(d) (-20) – (13) = -20 – 13 = –[20 + 13] = –33

(e) 23 – (-12) = 23 + 12 = 35

(f) (-32) – (-40) = -32 + 40 = 8

### Ex 6.3 Class 6 Maths Question 2.

Fill in the blanks with >, < or = sign.
(a) (-3) + (-6) _______ (-3) – (-6)
(b) (-21) – (-10) ______ (-31) + (-11)
(c) 45 – (-11) ______ 57 + (-4)
(d) (-25) – (-42) ______ (-42) – (-25)

Solution:
(a) (-3) + (-6) = – [3 + 6] = – 9 and (-3) – (-6) = (-3) + 6 = 3
Here, – 9 < 3
(-3) + (-6) < (-3) – (-6)

(b) (-21) – (-10) = (-21) + 10 = -11 and (-31) + (-11) = –(31 + 11) = –42
Here, -11 > -42
(-21) – (-10) > (-31) + (-11)

(c) 45 – (-11) = 45 + 11 = 56 and 57 + (-4) = 57 – 4 = 53
Here, 56 > 53
45 – (-11) > 57 + (-4)

(d) (-25) – (-42) = -25 + 42 = 17
and (-42) – (-25) = -42 + 25 = -17
Here, 17 > -17
(-25) – (-42) > (-42) – (-25)

### Ex 6.3 Class 6 Maths Question 3.

Fill in the blanks.
(a) (-8) + _____ = 0
(b) 13 + _____ = 0
(c) 12 + (-12) = _____
(d) (-4) + _____ = – 12
(e) _____ -15 = –10

Solution:
(a) (-8) + (additive inverse of -8) = 0
= (-8) + (8) = 0
Value in the blank space is 8.

(b) 13 + (additive inverse of 13) = 0
= 13 + (-13) = 0
Value in the blank space is –13.

(c) 12 + (-12) = 0 [ -12 is additive inverse of 12]
Value in the blank space is 0.

(d) (-4) + (-8) = -[4 + 8] = -12
Value in the blank space is -8.

(e) (+5) – 15 = -10
Value in the blank space is +5.

### Ex 6.3 Class 6 Maths Question 4.

Find:
(a) (-7) – 8 – (-25)
(b) (-13) + 32 – 8 – 1
(c) (-7) + (-8) + (-90)
(d) 50 – (-40) – (-2)

Solution:
(a) (-7) – 8 – (-25)
= (-7) – 8 + 25
= -15 + 25 = 10

(b) (-13) + 32 – 8 – 1
= (-13) + 32 – (8 + 1)
= 19 – 9
= 10

(c) (-7) + (-8) + (-90) = –(7 + 8) + (-90)
= -15 + (-90)
= -(15 + 90)
= -105

(d) 50 – (-40) – (-2)
= 50 – [-40 – 2]
= 50 – (-42)
= 50 + 42
= 92

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