NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2 are the part of NCERT Solutions for Class 6 Maths (Rationalised Contents). Here you can find the NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2.

NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2 (Rationalised Contents)

Ex 6.2 Class 6 Maths Question 1.

Using the number line write the integer which is:
(a) 3 more than 5
(b) 5 more than -5
(c) 6 less than 2
(d) 3 less than -2

Solution:
(a) 3 more than 5

Moving right 3 steps from 5, we reach at 8. Hence, 3 more than 5 is 8.

(b) 5 more than -5

Moving right 5 steps from -5, we reach at 0. Hence, 5 more than -5 is 0.

(c) 6 less than 2

Moving left 6 steps from 2, we reach at -4. Hence, 6 less than 2 is -4.

(d) 3 less than -2

Moving left 3 steps from -2, we reach at -5. Hence, 3 less than -2 is -5.

Ex 6.2 Class 6 Maths Question 2.

Use number line and add the following integers:
(a) 9 + (-6)
(b) 5 + (-11)
(c) (-1) + (-7)
(d) (- 5) + 10
(e) (-1) + (-2) + (-3)
(f) (-2) + 8 + (-4)

Solution:

Ex 6.2 Class 6 Maths Question 3.

(Ð°) 11 + (-7)
(b) (-13) + (+18)
(c) (-10) + (+19)
(d) (-250) + (+150)
(e) (-380) + (-270)
(f) (-217) + (-100)

Solution:
(a) 11 + (-7) = 4 + (+7) + (-7)
[
(+7) + (-7) = 0]
= 4 + 0 = 4
Hence, 11 + (-7) = 4

(b) (-13) + (+18) = (-13) + (+13) + (+5)
[
(-13) + (+13) = 0]
= 0 + (+ 5) = 5
Hence, (-13) + (+ 18) = 5

(c) (-10) + (+19) = (-10) + (+10) + (+9)
[
(-10) + (10) = 0] = 0 + (+9) = 9
Hence, (-10) + (19) = 9

(d) (-250) + (+150) = (-100) + (-150) + (+150)
= (-100) + 0 = -100  [
(-150) + (+150) = 0]
Hence, (-250) + (+150) = –100

(e) (-380) + (-270) = – [380 + 270] = (-650)
Hence, (-380) + (-270) = -650

(f) (-217) + (-100) = –[217 + 100] = (-317)

Hence, (-217) + (-100) = -317

Ex 6.2 Class 6 Maths Question 4.

Find the sum of:
(a) 137 and -354
(b) -52 and 52
(c) -312, 39 and 192
(d) -50, -200 and 300

Solution:
(a) 137 and -354
(137) + ( -354) = (-217)

(b) -52 and 52
(-52) + (+52) = 0  [
(-a) + (+ a) = 0]

(c) -312, 39 and 192
(-312) + (+ 39) + (+192)
= (-312) + (231)
= –81

(d) -50, -200 and 300
(-50) + (-200) + (+ 300)
= -(50 + 200) + (+300)
= (-250) + (+300)
= 50

Ex 6.2 Class 6 Maths Question 5.

Find the sum:
(a) (-7) + (-9) + 4 + 16
(b) (37) + (-2) + (-65) + (-8)

Solution:
(a) (-7) + (-9) + 4 + 16
= (-7) + (-9) + 4 + (+7) + (+ 9)
= (-7) + (+7) + (-9) + (+9) + 4
= 0 + 0 + 4 = 4   [
(-a) + (a) = 0]

(b) (37) + (-2) + (-65) + (-8)
= (+37) + (-75)
= (-38)

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