**NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.1****NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2****NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3**

**NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.2 ****(Rationalised Contents)**

**Ex 6.2 Class 6 Maths Question 1.**

Using the number line write the integer which is:(a) 3 more than 5

(b) 5 more than -5

(c) 6 less than 2

(d) 3 less than -2

**Solution:
**(a) 3 more than 5

Moving right 3 steps from 5, we reach at 8. Hence, 3 more than 5 is 8.

(b) 5 more than -5

Moving right 5 steps from -5, we reach at 0. Hence, 5 more than -5 is 0.

(c) 6 less than 2

Moving left 6 steps from 2, we reach at -4. Hence, 6 less than 2 is -4.

(d) 3 less than -2

Moving left 3 steps from -2, we reach at -5. Hence, 3 less than -2 is -5.

**Ex 6.2 Class 6 Maths Question 2.**

Use number line and add the following integers:(a) 9 + (-6)

(b) 5 + (-11)

(c) (-1) + (-7)

(d) (- 5) + 10

(e) (-1) + (-2) + (-3)

(f) (-2) + 8 + (-4)

**Solution:**

**Ex 6.2 Class 6 Maths Question 3.**

Add without using number line:(Ð°) 11 + (-7)

(b) (-13) + (+18)

(c) (-10) + (+19)

(d) (-250) + (+150)

(e) (-380) + (-270)

(f) (-217) + (-100)

**Solution:
**(a) 11 + (-7) = 4 + (+7) + (-7)

[∵ (+7) + (-7) = 0]

= 4 + 0 = 4

Hence, 11 + (-7) = 4

(b) (-13) + (+18) = (-13) + (+13) + (+5)

[∵ (-13) + (+13) = 0]

= 0 + (+ 5) = 5

Hence, (-13) + (+ 18) = 5

(c) (-10) + (+19) = (-10) + (+10) + (+9)

[∵ (-10) + (10) = 0] = 0 + (+9) = 9

Hence, (-10) + (19) = 9

(d) (-250) + (+150) = (-100) + (-150) + (+150)

= (-100) + 0 = -100 [∵ (-150)
+ (+150) = 0]

Hence, (-250) + (+150) = –100

(e) (-380) + (-270) = – [380 + 270] = (-650)

Hence, (-380) + (-270) = -650

(f) (-217) + (-100) = –[217 + 100] = (-317)

Hence, (-217) + (-100) = -317

**Ex 6.2 Class 6 Maths Question 4.**

Find the sum of:(a) 137 and -354

(b) -52 and 52

(c) -312, 39 and 192

(d) -50, -200 and 300

**Solution:
**(a) 137 and -354

(137) + ( -354) = (-217)

(b) -52 and 52

(-52) + (+52) = 0 [ ∵ (-a) + (+ a) = 0]

(c) -312, 39 and 192

(-312) + (+ 39) + (+192)

= (-312) + (231)

= –81

(d) -50, -200 and 300

(-50) + (-200) + (+ 300)

= -(50 + 200) + (+300)

= (-250) + (+300)

= 50

**Ex 6.2 Class 6 Maths Question 5.**

Find the sum:(a) (-7) + (-9) + 4 + 16

(b) (37) + (-2) + (-65) + (-8)

**Solution:
**(a) (-7) + (-9) + 4 + 16

= (-7) + (-9) + 4 + (+7) + (+ 9)

= (-7) + (+7) + (-9) + (+9) + 4

= 0 + 0 + 4 = 4 [∵ (-a) + (a) = 0]

(b) (37) + (-2) + (-65) + (-8)

= (+37) + (-75)

= (-38)

**Related Links:**

**NCERT Solutions for Maths Class 7**

**NCERT Solutions for Maths Class 8**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**