NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 are the part of NCERT Solutions for Class 7 Maths. Here you can find the NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2.

Ex 10.2 Class 7 Maths Question 1.

Construct ∆XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Solution:
Steps of construction:
(i) Draw a line segment XY = 4.5 cm.
(ii) With centre Y and radius 5 cm, draw an arc.
(iii) With centre X and radius 6 cm, draw another arc to meet the first arc at Z.
(iv) Join ZY and ZX.
(v) XYZ is the required triangle.

Ex 10.2 Class 7 Maths Question 2.

Construct an equilateral triangle of side 5.5 cm.

Solution:

Steps of construction:
(i) Draw a line segment BC = 5.5 cm.
(ii) With centres B and C and same radius of 5.5 cm, draw two arcs to meet each other at point A.
(iii) Join AB and AC.
(iv) ABC is the required equilateral triangle.

Ex 10.2 Class 7 Maths Question 3.

Draw ∆PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Solution:
Steps of construction:
(i) Draw a line segment QR = 3.5 cm.
(ii) With centres Q and R and same radius of 4 cm, draw two arcs to meet each other at point P.

(iii) Join PQ and PR.
(iv) PQR is the required triangle.
(v) Since PQ = PR = 4 cm, therefore, ∆PQR is an isosceles triangle.

Ex 10.2 Class 7 Maths Question 4.

Construct ∆ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

Solution:
Steps of construction:
(i) Draw a line segment BC = 6 cm.
(ii) With centres B and C and radius 2.5 cm and 6.5 cm, respectively, draw two arcs to meet each other at point A.
(iii) Join AB and AC.
(iv) ABC is the required triangle.