**NCERT
Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1**

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry
Ex 10.1 are the part of NCERT Solutions for Class 7 Maths. Here you can find
the NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1.

**NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5**

**Ex 10.1 Class 7 Maths Question 1.**

Draw a line, say AB, take a point C outside it.
Through C, draw a line parallel to AB using ruler and compasses only.**Solution:
Steps of construction:
**(i) Draw a line AB and take a point C above it.

(ii) Take any point D on the line AB.

(iii) Join the given point C to the point D and mark ∠1 to ∠CDB.

(iv) Draw ∠1 = ∠2 at C and produce the line to both sides.

(v) MN is the required line.

**Ex 10.1 Class 7 Maths Question 2.**

Draw a line l. Draw a perpendicular to l at any
point on l. On this perpendicular choose a point X, 4 cm away from l. Through
X, draw a line m parallel to l.**Solution: **

**Steps of construction:
**(i) Draw a line l and take any point P on it.

(ii) Draw a perpendicular at the point P to the line l and cut an arc PX = 4 cm.

(iv) m is the required line parallel to l through X.

Using properties of alternate angles, ∠1 = ∠2. Therefore, line m is parallel to line l.

**Ex 10.1 Class 7 Maths Question 3.**

Let l be a line and P be a point
not on l. Through P, draw a line m parallel to l. Now join P to any point Q on
l. Choose any other point R on m. Through R, draw a line parallel to PQ. Let
this meet l at S. What shape do the two sets of parallel lines enclose?**Solution:****
Steps of Construction:
**(i) Draw a line l and take any
point P outside l.

(ii) Draw a line m parallel to l through P.

(iii) Join P and Q.

(iv) PQ makes ∠1 with l and ∠2 with m which are equal angles.

(v) Take any point R on m and draw ∠3 equal to ∠2 to meet l at S such that PQ || RS.

(vi) Since l || m and PQ || RS. Therefore, PQSR is a parallelogram.

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