**NCERT
Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.1**

NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
Ex 11.1 are the part of NCERT Solutions for Class 7 Maths. Here you can find
the NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.1.

**NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.1****NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2****NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3****NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.4**

**Ex 11.1 Class 7 Maths Question 1.**

The length and the breadth of a
rectangular piece of land are 500 m and 300 m respectively. Find(i) its area

(ii) the cost of the land, if 1 m

^{2}of the land costs ₹ 10,000

**Solution:****
**Given: Length of the land, l = 500
m, Breadth of the land, b = 300 m

(i) Area of the land = l × b

= 500 m × 300 m = 1,50,000 m

^{2}

(ii) Cost of the land = ₹ 10,000 × 150000 = ₹ 1,50,00,00,000

**Ex
11.1 Class 7 Maths Question 2.**

Find the area of a square park whose perimeter is
320 m.**Solution:
**Given: Perimeter of the square park = 320 m

Side of the square park = Perimeter ÷ 4

= 320/4 m = 80 m

Area of the square park = Side × Side

= 80 m × 80 m = 6400 m

^{2}

**Ex
11.1 Class 7 Maths Question 3.**

Find the breadth of a rectangular plot of land, if
its area is 440 m^{2}and the length is 22 m. Also, find its perimeter.

**Solution:
**Given: Area of the rectangular plot = 440 m

^{2}

Length of the plot = 22 m

Breadth of the plot = Area ÷ Length = 440/22 = 20 m

Perimeter of the plot = 2[l + b] = 2[22 m + 20 m]

= 2 × 42 m = 84 m

**Ex 11.1 Class 7 Maths Question 4.**

The perimeter of a rectangular
sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area.**Solution:****
**Given: Perimeter of the rectangular
sheet = 100 cm

Length of the sheet = 35 cm

Perimeter of a rectangle = 2(l + b)

100 = 2(35 + b)

100/2 = 35 + b

⇒ 50 = 35 + b

⇒ b = 50 – 35 = 15 cm

∴ Breadth of the sheet = 15 cm

Area of the sheet = l × b = 35 cm × 15 cm

= 525 cm

^{2}

**Ex
11.1 Class 7 Maths Question 5.**

The area of a square park is same as of a
rectangular park. If the side of the square park is 60 m and the length of the
rectangular park is 90 m, find the breadth of the rectangular park.**Solution:
**Given: Side of the square park = 60 m

Length
of the rectangular park = 90 m

Let
the breadth of the rectangular park be b.

Area
of the rectangular park = Area of the square park

90 × b = 60 × 60

⇒ 90 × b = 3600

⇒ b = 3600/90

⇒ b = 40 m

Hence, the breadth of the rectangular park is 40 m.

**Ex
11.1 Class 7 Maths Question 6.**

A wire is in the shape of a rectangle. Its length is
40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a
square, what will be the measure of each side. Also find which shape encloses
more area?**Solution:
**Given: Length of the rectangle = 40 cm, Breadth of
the rectangle = 22 cm

Perimeter
of the rectangle = Length of the wire

= 2(l + b) = 2(40 cm +
22 cm)

= 2 × 62 cm = 124 cm

Now, the wire is rebent into the shape of a square.

Perimeter of the square = 124 cm

⇒ 4 × side = 124

∴ Side = 124/4 cm =
31 cm

So, the measure of each side of the square is 31 cm.

Area of the rectangular shape = l × b

= 40 cm × 22 cm

= 880 cm^{2}

Area of the square shape = (Side)^{2}

= (31)^{2} = 961 cm^{2}

Since, 961 cm^{2} > 880 cm^{2}

Hence, the square shape encloses more area.

**Ex
11.1 Class 7 Maths Question 7.**

The perimeter of a rectangle is 130 cm. If the
breadth of the rectangle is 30 cm, find its length. Also find the area of the
rectangle.**Solution:
**Given: Perimeter of the rectangle = 130 cm

Breadth of the rectangle = 30 cm

Perimeter of the rectangle = 2(l + b)

130 = 2(l + 30)

⇒ 130/2 = l + 30

⇒ 65 = l + 30

⇒ l = 65 – 30

∴ l = 35 cm

Area of the rectangle = l × b = 35 cm × 30 cm

= 1050 cm

^{2}

**Ex 11.1 Class 7 Maths Question 8.**

A door of length 2 m and breadth 1 m is fitted in a
wall. The length of the wall is 4.5 m and the breadth is 3.6 m. Find the cost
of white washing the wall, if the rate of white washing the wall is ₹ 20 per m^{2}.

**Solution:
**Given: Length of the wall = 4.5 m

Breadth of the wall = 3.6 m

Length of the door = 2 m

Breadth of the door = 1 m

Area of the wall = l × b = 4.5 m × 3.6 m = 16.20 m

^{2}

Area of the door = l × b = 2 m × 1 m = 2 m

^{2}

∴ Area of the wall to be whitewashed = Area of the wall – Area of the door

= 16.20 m

^{2}– 2 m

^{2 }= 14.20 m

^{2}

Cost of whitewashing = ₹ 20 × 14.20 = ₹ 284.00

Hence, the required cost of whitewashing is ₹ 284.

**You can also like these:**

**NCERT Solutions for Maths Class 8**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**

**NCERT Solutions for Maths Class 11**