**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.5**

NCERT Solutions for Class
8 Maths Chapter 4
Practical Geometry Ex 4.5 are the part of NCERT Solutions for Class 8 Maths.
Here you can find the NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex
4.5**.**

**Draw the following:**

**Ex 4.5 Class 8 Maths Question 1.**

The square READ with RE = 5.1 cm.**Solution:**

**Construction:**

Step 1: Draw a line segment RE = 5.1 cm.

Step 2: Draw an angle of 90° at E and cut EA = 5.1 cm.

Step 3: Draw two arcs from A and R with radius 5.1 cm to cut each other at D.

Step 4: Join RD and AD.

Thus, READ is the required square.

**Ex 4.5 Class 8
Maths Question 2.**

A rhombus whose diagonals are 5.2 cm and 6.4 cm
long.**Solution:**

**Construction:**

Step 1: Draw a line
segment AC = 6.4 cm.

Step 2: Draw the perpendicular bisector of AC at E.

Step 3: Draw two arcs with centre E and radius = ½ × 5.2 = 2.6 cm to cut the perpendicular bisector
of AC at B and D.

Step 4: Join AD, AB, BC and DC.

Thus, ABCD is the required rhombus.

**Ex 4.5 Class 8 Maths Question 3.**

A
rectangle with adjacent sides of lengths 5 cm and 4 cm.**Solution:**

**Steps of ****Construction:** Let the two
adjacent sides of a rectangle PQRS be PQ = 5 cm and QR = 4 cm.

Step 1: Draw a line segment PQ = 5 cm.

Step 2: Draw an angle of 90° at Q and cut QR = 4 cm.

Step 3: Draw an arc with centre R and radius 5 cm.

Step 4: Draw another arc with centre P and radius 4 cm to cut the previous arc at S.

Step 5: Join RS and PS.

Thus, PQRS is the required rectangle.

**Ex 4.5 Class 8 Maths Question 4.**

A
parallelogram OKAY where OK = 5.5 cm and KA = 4.2 cm. Is it unique?**Solution:**

**Construction:**

Step 1: Draw a line segment OK = 5.5 cm.

Step 2: Draw an angle of any measure (say 60°) at K and cut KA = 4.2 cm.

Step 3:
Draw an arc with centre A and radius 5.5 cm.

Step 4: Draw another arc with centre O and
radius 4.2 cm to cut the previous arc at Y.

Step 5: Join AY and OY.

Thus, OKAY is the required parallelogram.

No, it is not a unique parallelogram. The angle
of 60° made at K can be of measure other than 60°.

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