NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2

# NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2

## NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2

NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2 are the part of NCERT Solutions for Class 8 Maths. Here you can find the NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2.

### Ex 4.2 Class 8 Maths Question 1.

LI = 4 cm
IF = 3 cm
TL = 2.5 cm
LF = 4.5 cm
IT = 4 cm
OL = 7.5 cm
GL = 6 cm
GD = 6 cm
LD = 5 cm
OD = 10 cm
(iii) Rhombus BEND
BN = 5.6 cm
DE = 6.5 cm

Solution:
(i)
Let us draw a rough sketch first.

Steps of Construction:

Step 1: Draw a line segment LI = 4 cm.
Step 2: Draw an arc with centre I and radius 3 cm.
Step 3: Draw another arc with centre L and radius 4.5 cm to meet the previous arc at F.
Step 4: Join LF and IF.
Step 5: Draw an arc with centre L and radius 2.5 cm.
Step 6: Draw another arc with centre I and radius 4 cm to cut the previous arc at T.
Step 7: Join LT, IT and TF.
Thus, LIFT is the required quadrilateral.

(ii) Let us draw a rough sketch first.

Steps of Construction:

Step 1: Draw a line segment OL = 7.5 cm.
Step 2: Draw an arc with centre O and radius 10 cm.
Step 3: Draw another arc with centre L and radius 5 cm to meet the previous arc at D.
Step 4: Join OD and LD.
Step 5: Draw an arc with centre L and D with equal radii of 6 cm to cut each other at G.
Step 6: Join LG, DG and OG.
Thus, GOLD is the required quadrilateral.

(iii) Let us draw a rough sketch first.

Steps of Construction: We know that the diagonals of a rhombus bisect each other at the right angle.

Step 1: Draw a line segment BN = 5.6 cm.
Step 2: Draw the perpendicular bisector of BN at O.
Step 3: Draw two arcs with centre O and radius ½ × DE, i.e., ½ × 6.5 = 3.25 cm to cut the perpendicular bisector at D and E.
Step 4: Join BE, EN, ND and BD.
Thus, BEND is the required rhombus.

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