**NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.2**

NCERT Solutions for Class
8 Maths Chapter 4
Practical Geometry Ex 4.2 are the part of NCERT Solutions for Class 8 Maths.
Here you can find the NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex
4.2**.**

**Ex 4.2 Class 8 Maths
Question 1.**

Construct the following quadrilaterals.**(i)**Quadrilateral LIFT

LI = 4 cm

IF = 3 cm

TL = 2.5 cm

LF = 4.5 cm

IT = 4 cm

**(ii)**Quadrilateral GOLD

OL = 7.5 cm

GL = 6 cm

GD = 6 cm

LD = 5 cm

OD = 10 cm

**(iii)**Rhombus BEND

BN = 5.6 cm

DE = 6.5 cm

**Solution:
(i) **Let us draw a rough sketch first.

**Steps of**

**Construction:**

Step 1: Draw a line
segment LI = 4 cm.

Step 2: Draw an arc with centre I and radius 3 cm.

Step 3: Draw another arc with centre L and radius 4.5 cm to meet the previous
arc at F.

Step 4: Join LF and IF.

Step 5: Draw an arc with centre L and radius 2.5 cm.

Step 6: Draw another arc with centre I and radius 4 cm to cut the previous arc
at T.

Step 7: Join LT, IT and TF.

Thus, LIFT is the required quadrilateral.

**(ii) **Let us draw a rough sketch first.

**Steps of**

**Construction:**

Step 1: Draw a line
segment OL = 7.5 cm.

Step 2: Draw an arc with centre O and radius 10 cm.

Step 3: Draw another arc with centre L and radius 5 cm to meet the previous arc
at D.

Step 4: Join OD and LD.

Step 5: Draw an arc with centre L and D with equal radii of 6 cm to cut each
other at G.

Step 6: Join LG, DG and OG.

Thus, GOLD is the required quadrilateral.

**(iii) **Let us draw a rough sketch first.

**Steps of**

**Construction:**We know that the diagonals of a rhombus bisect each other at the right angle.

Step 1: Draw a line
segment BN = 5.6 cm.

Step 2: Draw the perpendicular bisector of BN at O.

Step 3: Draw two arcs with centre O and radius ½ × DE, i.e., ½ × 6.5 = 3.25 cm to cut the perpendicular bisector
at D and E.

Step 4: Join BE, EN, ND and BD.

Thus, BEND is the required rhombus.

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