**NCERT Solutions for Class 11 Maths Chapter 10 Conic Sections Ex 10.4**

**In each of the Exercises 1 to 6, find the coordinates of the foci and
the vertices, the eccentricity and the length of the latus rectum of the
hyperbolas.**

**Ex 10.4 Class 11 Maths Question 1.**

x^{2}/16 − y

^{2}/9 = 1

**Solution:**

The given equation of the hyperbola is:

**Ex 10.4 Class 11 Maths Question 2.**

y^{2}/9 − x

^{2}/27 = 1

**Solution:**

The given equation of the hyperbola is:

**Ex 10.4 Class 11
Maths Question 3.**

### 9y^{2} – 4x^{2} = 36

**Solution:**

The given equation of the hyperbola is:

9y^{2} – 4x^{2} = 36

**Ex 10.4 Class 11
Maths Question 4.**

16x^{2}– 9y

^{2}= 576

**Solution:**

The given equation of the hyperbola is:

16x^{2} – 9y^{2} = 576

**Ex 10.4 Class 11 Maths Question
5.**

5y^{2}– 9x

^{2}= 36

**Solution:**

The given equation of the hyperbola is:

5y^{2} –
9x^{2} = 36

**Ex 10.4 Class 11
Maths Question 6.**

49y^{2}– 16x

^{2}= 784

**Solution:**

The given equation of the hyperbola is:

49y^{2} – 16x^{2} = 784

**In each of the Exercises 7 to
15, find the equations of the hyperbola satisfying the given conditions.**

**Ex 10.4 Class 11
Maths Question 7.**

Vertices (±2, 0), foci (±3, 0)

**Solution:**

The vertices are (±2, 0) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 10.4 Class 11 Maths Question
8.**

Vertices (0, ±5), foci (0, ±8)

**Solution:**

The vertices are (0, ±5) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 10.4 Class 11
Maths Question 9.**

Vertices (0, ±3), foci (0, ±5)

**Solution:**

The vertices are (0, ±3) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 10.4 Class 11
Maths Question 10.**

Foci (±5, 0), the transverse axis is of length 8.

**Solution:**

Here, the foci are (±5, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 10.4 Class 11
Maths Question 11.**

Foci (0, ±13), the conjugate axis is of length 24.

**Solution:**

Here, the foci are (0, ±13) which lie on y-axis. So, the equation of the
hyperbola in standard form is:

**Ex 10.4 Class 11 Maths Question 12.**

Foci (±3√5, 0), the latus rectum is of length 8.

**Solution: **

Here, the foci are (±3√5, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 10.4 Class 11
Maths Question 13.**

Foci (±4, 0), the latus rectum is of length 12.

**Solution:**

Here, the foci are (±4, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 10.4 Class 11 Maths Question 14.**

Vertices (±7, 0), e = 4/3.

**Solution:**

Here, the vertices are (±7, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 10.4 Class 11 Maths Question 15.**

Foci (0, ±√10), passing
through (2, 3).

**Solution: **

Here, the foci are (0, ±√10) which lie on
y-axis. So, the equation of the hyperbola in standard form is:

**Related Links:**

**NCERT Solutions for Maths Class 9**