NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2

# NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2

NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2 are the part of NCERT Solutions for Class 6 Maths (Rationalised Contents). Here you can find the NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2.

## NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2 (Rationalised Contents)

### Ex 10.2 Class 6 Maths Question 1.

Find the areas of the following figures by counting square:

Solution:
(a) Number of full squares = 9
Area of 1 square = 1 sq. unit
Area of 9 squares = 9 × 1 sq. unit
= 9 sq. units.
Therefore, the area of the figure is 9 sq. units.

(b) Number of full squares = 5
Area of the figure = 5 × 1 sq. unit = 5 sq. units

(c) Number of full squares = 2
Number of half squares = 4
Area of the figure = 2 × 1 + 4 × ½ = 2 + 2
= 4 sq. units

(d) Number of full squares = 8
Area of the figure = 8 × 1 sq. unit
= 8 sq. units

(e) Number of full squares = 10
Area of the figure = 10 × 1 sq. unit = 10 sq. units

(f) Number of full squares = 2
Number of half squares = 4
Area of the figure = (2 × 1 + 4 × ½)
= (2 + 2) sq. units = 4 sq. units

(g) Number of full squares = 4
Number of half squares = 4
Area of the figure = (4 × 1 + 4 × ½)
= (4 + 2) sq. units = 6 sq. units

(h) Number of full squares = 5
Area of the figure = 5 × 1 sq. unit = 5 sq. units

(i) Number of full squares = 9
Area of the figure = 9 × 1 sq. units
= 9 sq. units

(j) Number of full squares = 2
Number of half squares = 4
Area of the figure = (2 × 1 + 4 × ½) sq. units
= (2 + 2) sq. units = 4 sq. units
(k) Number of full squares = 4
Number of half squares = 2
Area of the figure = (4 × 1 + 2 × ½) sq. units
= (4 + 1) sq. units
= 5 sq. units

(l) Number of full squares = 4
Number of squares more than half = 3
Number of half squares = 2
Area of the figure = (4 × 1 + 3 × 1 + 2 × ½) sq. units
= (4 + 3 + 1) sq. units = 8 sq. units

(m) Number of full squares = 6

Number of squares more than half = 8
Area of the figure = (6 × 1 + 8 × 1) sq. units
= (6 + 8) sq. units
= 14 sq. units

(n) Number of full squares = 9
Number of squares more than half = 9
Area of the figure = (9 × 1 + 9 × 1) sq. units
= (9 + 9) sq. units = 18 sq. units

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