**NCERT
Solutions for Class 6 Maths Knowing Our Numbers Ex 1.2**

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers
Ex 1.2 are the part of NCERT Solutions for Class 6 Maths. Here you can find the
NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2.

**NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.1****NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2****NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.3**

**Ex 1.2 Class 6 Maths Question
1.**

A book exhibition was held for four days in a
school. The number of tickets sold at the counter on the first, second, third
and final day was respectively 1094, 1812, 2050 and 2751. Find the total number
of tickets sold on all the four days.**Solution:
**The number of tickets sold on the first day = 1094

The number of tickets sold on the second day = 1812

The number of tickets sold on the third day = 2050

The number of tickets sold on the final day = 2751

∴ Total number of tickets sold on all the four days

= 1094 + 1812 + 2050 + 2751 = 7707

**Ex 1.2 Class 6 Maths Question
2.**

Shekhar is a famous cricket player. He has so far
scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many
more runs does he need?**Solution:**

Shekhar has scored 6980 runs so far.

He wishes to complete 10,000 runs.

Therefore, the total number of runs needed by him

= 10,000 – 6980 = 3020 runs

**Ex 1.2 Class 6 Maths Question
3.**

In an election, the successful candidate registered
5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did
the successful candidate win the election?**Solution:
**The number of votes secured by the successful
candidate = 5,77,500

The number of votes secured by his nearest rival = 3,48,700

Therefore, the margin of votes the successful candidate got to win the election = 5,77,500 – 3,48,700 = 2,28,800

**Ex 1.2 Class 6 Maths Question
4.**

Kirti bookstore sold books worth ₹2,85,891 in the
first week of June and books worth ₹4,00,768 in the second week of the month.
How much was the sale for the two weeks together? In which week was the sale
greater and by how much?**Solution:
**Books sold in the first week of June worth ₹2,85,891.

Books sold in the second week of the month worth ₹4,00,768.

Therefore, the total sale of books in the two weeks together

= ₹2,85,891 + ₹4,00,768 = ₹6,86,659

In the second week of the month, the sale of books was greater.

Difference of the sale of books in two weeks

= ₹4,00,768 – ₹2,85,891 = ₹1,14,877

Hence, in the second week of June, the sale of books was more by ₹1,14,877.

**Ex 1.2 Class 6 Maths Question
5.**

Find the difference between the greatest and the
least numbers that can be written using the digits 6, 2, 7, 4, 3 each only
once.**Solution:
**The given digits are 6, 2, 7, 4 and 3.

The greatest number = 76432

The least number = 23467

Therefore, difference = 76432 – 23467 = 52,965

**Ex 1.2 Class 6 Maths Question
6.**

A machine, on an average, manufactures 2825 screws a
day. How many screws did it produce in the month of January 2006?**Solution:
**The number of screws manufactured in a day = 2825

The number of screws manufactured in the month of January = 31 × 2825 = 87,575

**Ex 1.2 Class 6 Maths Question
7.**

A merchant had ₹78,592 with her. She placed an order
for purchasing 40 radio sets at ₹1200 each. How much money will remain with her
after the purchase?**Solution:
**The amount of money with the merchant = ₹78,592

The number of radio sets = 40

The price of one radio set = ₹1200

Therefore, the cost of 40 radio sets = ₹1200 × 40 = ₹48,000

Remaining money with the merchant = ₹78,592 – ₹48000 = ₹30,592

Hence, the amount of ₹30,592 will remain with the merchant after purchasing the radio sets.

**Ex 1.2 Class 6 Maths Question
8.**

A student multiplied 7236 by 65 instead of
multiplying by 56. By how much was his answer greater than the correct answer?**Solution:
**The student has multiplied 7236 by 65 instead of
multiplying by 56.

Difference between the two multiplications = (65 – 56) × 7236 = 9 × 7236 = 65124

(No need to do both the multiplications)

Hence, the answer greater than the correct answer is 65,124.

**Ex
1.2 Class 6 Maths Question 9.**

To stitch a shirt, 2 m 15 cm cloth is needed. Out of
40 m cloth, how many shirts can be stitched and how much cloth will remain?

**Solution:
**The total length of the cloth = 40 m = 40 × 100 cm =
4000 cm

Cloth needed to stitch a shirt = 2 m 15 cm = 2 × 100 + 15 cm = 215 cm

Therefore, the number of shirts stitched = 4000/215

So, the number of shirts stitched = 18 and the remaining cloth = 130 cm = 1 m 30 cm

**Ex 1.2 Class 6 Maths Question
10.**

Medicine is packed in boxes, each weighing 4 kg 500
g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?**Solution:**

The weight of one box = 4 kg 500 g = 4 × 1000 + 500 = 4500 g

The van can carry a maximum of 800 kg = 800 × 1000 = 8,00,000 g

The number of boxes that can be loaded in the van = 8,00,000
÷ 4500

**Ex 1.2 Class 6 Maths Question
11.**

The distance between the school and the house of a
student is 1 km 875 m. Every day she walks both ways. Find the total distance
covered by her in six days.**Solution:
**The distance between the school and the house of the
student

= 1 km 875 m = (1000 + 875) m = 1875 m

The distance travelled by the student in both ways = 2 × 1875 = 3750 m

The distance travelled in 6 days = 3750 m × 6 = 22,500 m = 22 km 500 m

Hence, the total distance covered in six days is 22 km 500 m.

**Ex
1.2 Class 6 Maths Question 12.**

A vessel has 4 litres and 500 mL of curd. In how
many glasses, each of 25 mL capacity, can it be filled?**Solution:
**The quantity of curd in the vessel = 4 L 500 mL = (4
× 1000 + 500) mL = 4500 mL

The capacity of 1 glass = 25 mL

Therefore, the number of glasses that can be filled = 4500/25 = 180

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