NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2

# NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2

## NCERT Solutions for Class 6 Maths Knowing Our Numbers Ex 1.2

NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2 are the part of NCERT Solutions for Class 6 Maths. Here you can find the NCERT Solutions for Class 6 Maths Chapter 1 Knowing Our Numbers Ex 1.2.

### Ex 1.2 Class 6 Maths Question 1.

A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.

Solution:
The number of tickets sold on the first day = 1094
The number of tickets sold on the second day = 1812
The number of tickets sold on the third day = 2050
The number of tickets sold on the final day = 2751
Total number of tickets sold on all the four days

= 1094 + 1812 + 2050 + 2751 = 7707

### Ex 1.2 Class 6 Maths Question 2.

Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?

Solution:
Shekhar has scored 6980 runs so far.
He wishes to complete 10,000 runs.
Therefore, the total number of runs needed by him

= 10,000 – 6980 = 3020 runs

### Ex 1.2 Class 6 Maths Question 3.

In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?

Solution:
The number of votes secured by the successful candidate = 5,77,500
The number of votes secured by his nearest rival = 3,48,700
Therefore, the margin of votes the successful candidate got to win the election = 5,77,500 – 3,48,700 = 2,28,800

### Ex 1.2 Class 6 Maths Question 4.

Kirti bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?

Solution:
Books sold in the first week of June worth ₹2,85,891.
Books sold in the second week of the month worth ₹4,00,768.
Therefore, the total sale of books in the two weeks together
= ₹2,85,891 + ₹4,00,768 = ₹6,86,659
In the second week of the month, the sale of books was greater.
Difference of the sale of books in two weeks
= ₹4,00,768 – ₹2,85,891 = ₹1,14,877
Hence, in the second week of June, the sale of books was more by ₹1,14,877.

### Ex 1.2 Class 6 Maths Question 5.

Find the difference between the greatest and the least numbers that can be written using the digits 6, 2, 7, 4, 3 each only once.

Solution:
The given digits are 6, 2, 7, 4 and 3.
The greatest number = 76432
The least number = 23467
Therefore, difference = 76432 – 23467 = 52,965

### Ex 1.2 Class 6 Maths Question 6.

A machine, on an average, manufactures 2825 screws a day. How many screws did it produce in the month of January 2006?

Solution:
The number of screws manufactured in a day = 2825
The number of screws manufactured in the month of January = 31 × 2825 = 87,575

### Ex 1.2 Class 6 Maths Question 7.

A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1200 each. How much money will remain with her after the purchase?

Solution:
The amount of money with the merchant = ₹78,592
The number of radio sets = 40
The price of one radio set = ₹1200
Therefore, the cost of 40 radio sets = ₹1200 × 40 = ₹48,000
Remaining money with the merchant = ₹78,592 – ₹48000 = ₹30,592
Hence, the amount of ₹30,592 will remain with the merchant after purchasing the radio sets.

### Ex 1.2 Class 6 Maths Question 8.

A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?

Solution:
The student has multiplied 7236 by 65 instead of multiplying by 56.
Difference between the two multiplications = (65 – 56) × 7236 = 9 × 7236 = 65124
(No need to do both the multiplications)

### Ex 1.2 Class 6 Maths Question 9.

To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?

Solution:
The total length of the cloth = 40 m = 40 × 100 cm = 4000 cm
Cloth needed to stitch a shirt = 2 m 15 cm = 2 × 100 + 15 cm = 215 cm
Therefore, the number of shirts stitched = 4000/215

So, the number of shirts stitched = 18 and the remaining cloth = 130 cm = 1 m 30 cm

### Ex 1.2 Class 6 Maths Question 10.

Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

Solution:
The weight of one box = 4 kg 500 g = 4 × 1000 + 500 = 4500 g
The van can carry a maximum of 800 kg = 800 × 1000 = 8,00,000 g

The number of boxes that can be loaded in the van = 8,00,000 ÷ 4500

Therefore, 177 boxes can only be loaded in the van.

### Ex 1.2 Class 6 Maths Question 11.

The distance between the school and the house of a student is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.

Solution:
The distance between the school and the house of the student

= 1 km 875 m = (1000 + 875) m = 1875 m
The distance travelled by the student in both ways = 2 × 1875 = 3750 m
The distance travelled in 6 days = 3750 m × 6 = 22,500 m = 22 km 500 m
Hence, the total distance covered in six days is 22 km 500 m.

### Ex 1.2 Class 6 Maths Question 12.

A vessel has 4 litres and 500 mL of curd. In how many glasses, each of 25 mL capacity, can it be filled?

Solution:
The quantity of curd in the vessel = 4 L 500 mL = (4 × 1000 + 500) mL = 4500 mL
The capacity of 1 glass = 25 mL
Therefore, the number of glasses that can be filled = 4500/25 = 180

You can also like these:

NCERT Solutions for Maths Class 7

NCERT Solutions for Maths Class 8

NCERT Solutions for Maths Class 9

NCERT Solutions for Maths Class 10

NCERT Solutions for Maths Class 11

NCERT Solutions for Maths Class 12