NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its
Properties Ex 6.2 are the part of NCERT Solutions for Class 7 Maths (Rationalised Contents). Here you
can find the NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its
Properties Ex 6.2.

**NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.1****NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2****NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.3****NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.4****NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.5**

**NCERT Solutions for Class 7 Maths Chapter 6 The Triangle and its Properties Ex 6.2 ****(Rationalised Contents)**

**Ex 6.2 Class 7 Maths Question 1.**

Find the value of the unknown exterior angle *x*in the following diagrams:

**Solution:**

(i) ∠x = 70° + 50° = 120° (Exterior angle is equal to the sum of its opposite interior angles)

(ii) ∠x = 45°+ 65° = 110° (Exterior angle is equal to the sum of its opposite interior angles)

(iii) ∠x = 40° + 30° = 70° (Exterior angle is equal to the sum of its opposite interior angles)

(iv) ∠x = 60° + 60° = 120° (Exterior angle is equal to the sum of its opposite interior angles)

(v) ∠x = 50° + 50° =100° (Exterior angle is equal to the sum of its opposite interior angles)

(vi) ∠x = 60° + 30° = 90° (Exterior angle is equal to the sum of its opposite interior angles)

**Ex 6.2 Class 7 Maths Question 2.**

Find the value of the unknown interior angle *x*in the following figures:

**Solution:
**(i) ∠x + 50° = 115° (Exterior
angle of a triangle)

∴ ∠x = 115° – 50° = 65°

(ii) ∠x + 70° = 100° (Exterior angle of a triangle)

∴ ∠x = 100° – 70° = 30°

(iii) ∠ x + 90° = 125° (Exterior angle of a right triangle)

∴ ∠x = 125° – 90° = 35°

(iv) ∠x + 60° = 120° (Exterior angle of a triangle)

∴ ∠x = 120° – 60° = 60°

(v) ∠x + 30° = 80° (Exterior angle of a triangle)

∴ ∠x = 80° – 30° = 50°

(vi) ∠ x + 35° = 75° (Exterior angle of a triangle)

∴ ∠ x = 75° – 35° = 40°

**Related Links:**

**NCERT Solutions for Maths Class 8**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**