**NCERT
Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1**

NCERT
Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 are the part of NCERT Solutions for
Class 7 Maths. Here you can find the NCERT Solutions for Class 7 Maths Chapter
5 Lines and Angles Ex 5.1.

**NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1****NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.2**

**Ex 5.1 Class 7 Maths Question 1.**

Find the complement of each of the following angles:**Solution:**

(i) The complement of 20° = 90° – 20° = 70°

(ii) The complement of 63° = 90° – 63° = 27°

(iii) The complement of 57° = 90° – 57° = 33°

**Ex 5.1 Class 7 Maths Question 2.**

Find the supplement of each of the following angles:

**Solution:
**(i) The supplement of 105° = 180° – 105° = 75°

(ii) The supplement of 87° = 180° – 87° = 93°

(iii) The supplement of 154° = 180° – 154° = 26°

**Ex 5.1 Class 7 Maths Question 3.**

Identify which of the following
pairs of angles are complementary and which are supplementary?(i) 65°, 115°

(ii) 63°, 27°

(iii) 112°, 68°

(iv) 130°, 50°

(v) 45°, 45°

(vi) 80°, 10°

**Solution:****
**(i) 65° + 115° = 180°

The given angles are supplementary angles.

(ii) 63° + 27° = 90°

The given angles are complementary angles.

(iii) 112° + 68° = 180°

The given angles are supplementary angles.

(iv) 130° + 50° = 180°

The given angles are supplementary angles.

(v) 45° + 45° = 90°

The given angles are complementary angles.

(vi) 80° + 10° = 90°

The given angles are complementary angles.

**Ex
5.1 Class 7 Maths Question 4.**

Find the angle which is equal to its complement.**Solution:
**Let the required angle be x°.

Its complement is (90 – x)°.

Now, x = 90 – x ⇒ x + x = 90

⇒ 2x = 90 ∴ x = 90/2 = 45°

Thus, the required angle is 45° which is equal to its complement.

**Ex
5.1 Class 7 Maths Question 5.**

Find the angle which is equal to its supplement.**Solution:
**Let the required angle be x°.

Its supplement is (180 – x)°.

Now, x = 180 – x

⇒ x + x = 180

⇒ 2x = 180°

∴ x = 180°/2 = 90°

Thus, the required angle is 90° which is equal to its supplement.

**Ex 5.1 Class 7 Maths Question 6.**

In the given figure, ∠1 and ∠2 are supplementary angles.If ∠1 is decreased, what changes should take place in ∠2 so that both the angles still remain supplementary.

**Solution:
**We have given that: ∠1 + ∠2 = 180°

If ∠1 is decreased by some degrees, then ∠2 will be increased by the same degree so that the two angles still remain supplementary.

**Ex 5.1 Class 7 Maths Question 7.**

Can two angles be supplementary if both of them are:(i) acute?

(ii) obtuse?

(iii) right?

**Solution: **

(i) Since, acute angle < 90°

∴ Acute angle + acute angle < 90° + 90° < 180°

Thus, the two acute angles cannot be supplementary
angles.

(ii) Since, obtuse angle > 90°

∴ Obtuse angle + obtuse angle > 90° + 90° > 180°

Thus, the two obtuse angles cannot be supplementary angles.

(iii) Since, right angle = 90°

∴ Right angle + right angle = 90° + 90° = 180°

Thus, the two right angles are supplementary angles.

**Ex 5.1 Class 7 Maths Question 8.**

An angle is greater than 45°. Is its complementary
angle greater than 45° or equal to 45° or less than 45 °?**Solution:
**Given angle is greater than 45°.

Let the given angle be x°.

∴ x > 45

The complement of x° = 90° – x° < 45° [ ∵ x > 45°]

Thus, the required angle must be less than 45°.

**Ex 5.1 Class 7 Maths Question 9.**

In the following figure:(i) Is ∠1 adjacent to ∠2?

(ii) Is ∠AOC adjacent to ∠AOE?

(iii) Do ∠COE and ∠EOD form a linear pair?

(iv) Are ∠BOD and ∠DOA supplementary?

(v) Is ∠1 vertically opposite to ∠4?

(vi) What is the vertically opposite angle of ∠5?

**Solution:
**(i) Yes, ∠1 is adjacent to ∠2.

(ii) No, ∠AOC is not adjacent to ∠AOE. [∵ OC and OE do not lie on either side of common arm OA] .

(iii) Yes, ∠COE and ∠EOD form a linear pair of angles.

(iv) Yes, ∠BOD and ∠DOA are supplementary angles. [∵ ∠BOD + ∠DOA = 180°]

(v) Yes, ∠1 is vertically opposite to ∠4.

(vi) The vertically opposite angle of ∠5 is ∠2 + ∠3, i.e., ∠BOC.

**Ex 5.1 Class 7 Maths Question 10.**

Indicate which pairs of angles are:(i) Vertically opposite angles

(ii) Linear pairs

**Solution:
**(i) The vertically opposite angles are: ∠1 and ∠4, ∠5 and (∠2 + ∠3)

(ii) The linear pairs are: ∠1 and ∠5, ∠4 and ∠5

**Ex 5.1 Class 7 Maths Question 11.**

In the following figure, is ∠1 adjacent to ∠2? Give reasons.**Solution:
**No, ∠1 and ∠2 are not adjacent angles.

Reasons: They have no common vertex.

**Ex 5.1 Class 7 Maths Question 12.**

Find the values of the angles x, y and z in each of
the following:**Solution:
**(i) ∠x = ∠55° (Vertically
opposite angles)

∠x + ∠y = 180° (Linear pair angles)

55° + ∠y = 180°

∴ ∠y = 180° – 55° = 125°

∠y = ∠z (Vertically opposite angles)

125° = ∠z

Hence, ∠x = 55°, ∠y = 125° and ∠z = 125°

(ii) 25° + x + 40° = 180° (Sum of the angles on a straight line)

65° + x = 180°

∴ x = 180° – 65° = 115°

40° + y = 180° (Linear
pair angles)

∴ y = 180° – 40° = 140°

y + z = 180° (Linear
pair angles)

140° + z = 180°

∴ z = 180° – 140° = 40°

Hence, x = 115°, y = 140° and z = 40°

**Ex 5.1 Class 7 Maths Question 13.**

Fill in the blanks:(i) If two angles are complementary, then the sum of their measures is ______ .

(ii) If two angles are supplementary, then the sum of their measures is ______ .

(iii) Two angles forming a linear pair are ______ .

(iv) If two adjacent angles are supplementary, they form a ______ .

(v) If two lines intersect at a point, then the vertically opposite angles are always ______ .

(vi) If two lines intersect at a point, and if one pair of vertically opposite angles are acute angles, then the other pair of vertically opposite angles are ______ .

**Solution:
**(i) 90°

(ii) 180°

(iii) supplementary

(iv) linear pair

(v) equal

(vi) obtuse angles

**Ex 5.1 Class 7 Maths Question 14.**

In the given figure, name the following pairs of
angles.(i) Obtuse vertically opposite angles

(ii) Adjacent complementary angles

(iii) Equal supplementary angles

(iv) Unequal supplementary angles

(v) Adjacent angles that do not form a linear pair

**Solution:
**(i) ∠BOC and ∠AOD are obtuse vertically opposite angles.

(ii) ∠AOB and ∠AOE are adjacent complementary angles.

(iii) ∠EOB and ∠EOD are equal supplementary angles.

(iv) ∠EOA and ∠EOC are unequal supplementary angles.

(v) ∠AOB and ∠AOE, ∠AOE and ∠EOD, ∠EOD and ∠COD are adjacent angles that do not form a linear pair.

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