NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1

NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1

NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 are the part of NCERT Solutions for Class 7 Maths (Rationalised Contents). Here you can find the NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1.



NCERT Solutions for Class 7 Maths Chapter 5 Lines and Angles Ex 5.1 (Rationalised Contents)


Ex 5.1 Class 7 Maths Question 1.

Find the complement of each of the following angles:

Solution:
(i) The complement of 20° = 90° – 20° = 70°
(ii) The complement of 63° = 90° – 63° = 27°
(iii) The complement of 57° = 90° – 57° = 33°

 

Ex 5.1 Class 7 Maths Question 2.

Find the supplement of each of the following angles:

Solution:
(i) The supplement of 105° = 180° – 105° = 75°
(ii) The supplement of 87° = 180° – 87° = 93°
(iii) The supplement of 154° = 180° – 154° = 26°

 

Ex 5.1 Class 7 Maths Question 3.

Identify which of the following pairs of angles are complementary and which are supplementary?
(i) 65°, 115°
(ii) 63°, 27°
(iii) 112°, 68°
(iv) 130°, 50°
(v) 45°, 45°
(vi) 80°, 10°

Solution:
(i) 65° + 115° = 180°
The given angles are supplementary angles.
(ii) 63° + 27° = 90°
The given angles are complementary angles.
(iii) 112° + 68° = 180°
The given angles are supplementary angles.
(iv) 130° + 50° = 180°
The given angles are supplementary angles.
(v) 45° + 45° = 90°
The given angles are complementary angles.
(vi) 80° + 10° = 90°
The given angles are complementary angles.

 

Ex 5.1 Class 7 Maths Question 4.

Find the angle which is equal to its complement.

Solution:
Let the required angle be x°.
Its complement is (90 – x)°.
Now, x = 90 – x
x + x = 90
2x = 90 x = 90/2 = 45°
Thus, the required angle is 45° which is equal to its complement.

 

Ex 5.1 Class 7 Maths Question 5.

Find the angle which is equal to its supplement.

Solution:
Let the required angle be x°.
Its supplement is (180 – x)°.
Now, x = 180 – x
x + x = 180
2x = 180°
 x = 180°/2 = 90°
Thus, the required angle is 90° which is equal to its supplement.

 

Ex 5.1 Class 7 Maths Question 6.

In the given figure, 1 and 2 are supplementary angles.
If
1 is decreased, what changes should take place in 2 so that both the angles still remain supplementary.

Solution:
We have given that: 
1 + 2 = 180°
If
1 is decreased by some degrees, then 2 will be increased by the same degree so that the two angles still remain supplementary.

 

Ex 5.1 Class 7 Maths Question 7.

Can two angles be supplementary if both of them are:
(i) acute?
(ii) obtuse?
(iii) right?

Solution:

(i) Since, acute angle < 90°

Acute angle + acute angle < 90° + 90° < 180°

Thus, the two acute angles cannot be supplementary angles.

(ii) Since, obtuse angle > 90°
Obtuse angle + obtuse angle > 90° + 90° > 180°
Thus, the two obtuse angles cannot be supplementary angles.

(iii) Since, right angle = 90°
Right angle + right angle = 90° + 90° = 180°
Thus, the two right angles are supplementary angles.

 

Ex 5.1 Class 7 Maths Question 8.

An angle is greater than 45°. Is its complementary angle greater than 45° or equal to 45° or less than 45 °?

Solution:
Given angle is greater than 45°.
Let the given angle be x°.
x > 45
The complement of x° = 90° – x° < 45°       [
x > 45°]
Thus, the required angle must be less than 45°.


Ex 5.1 Class 7 Maths Question 9.

Fill in the blanks:
(i) If two angles are complementary, then the sum of their measures is ______ .
(ii) If two angles are supplementary, then the sum of their measures is ______ .
(iii) If two adjacent angles are supplementary, they form a ______ .

Solution:
(i) 90°
(ii) 180°
(iii) linear pair

 

Ex 5.1 Class 7 Maths Question 10.

In the given figure, name the following pairs of angles.
(i) Obtuse vertically opposite angles
(ii) Adjacent complementary angles
(iii) Equal supplementary angles
(iv) Unequal supplementary angles
(v) Adjacent angles that do not form a linear pair

Solution:
(i) BOC and AOD are obtuse vertically opposite angles.
(ii)
AOB and AOE are adjacent complementary angles.
(iii)
EOB and EOD are equal supplementary angles.
(iv)
EOA and EOC are unequal supplementary angles.
(v)
AOB and AOE, AOE and EOD, EOD and COD are adjacent angles that do not form a linear pair.


Related Links:

NCERT Solutions for Maths Class 8

NCERT Solutions for Maths Class 9

NCERT Solutions for Maths Class 10

NCERT Solutions for Maths Class 11

NCERT Solutions for Maths Class 12

Please do not enter any spam link in the comment box.

Post a Comment (0)
Previous Post Next Post