**NCERT Solutions for Class 8 Maths Chapter 16
Playing with Numbers Ex 16.2**

NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers
Ex 16.2 are the part of NCERT Solutions for Class 8 Maths. Here you can find
the NCERT Solutions for Class 8 Maths Chapter 16 Playing
with Numbers Ex 16.2.

**NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.1****NCERT Solutions for Class 8 Maths Chapter 16 Playing with Numbers Ex 16.2**

**Ex 16.2 Class 8 Maths Question 1.**

If 21*y*5 is a multiple of 9, where y is a digit, what is the value of

*y*?

**Solution:**

Since the number 21*y*5 is divisible by 9.

So, the sum of its digits 2 + 1 + y + 5 = 8 + y is divisible by 9.

∴ (8 + y) is either 0 or 9 or 18 or 27 …

But since y is a digit, so (8 + y) must be equal to 9.

i.e., 8 + y = 9 ⇒ y = 9 – 8 = 1

Thus, y = 1.

**Ex 16.2 Class 8
Maths Question 2.**

If 31*z*5 is a multiple of 9, where

*z*is a digit, what is the value of

*z*?

**Solution:**

Since the number 31z5 is divisible by 9.

So, the sum of its digits 3 + 1 + z + 5 = 9 + z is divisible by 9.

∴ (9 + z) is either 0 or 9 or 18 or 27 …

But since z is a digit, so (9 + z) must be equal to 9 or 18…

i.e., 9 + z = 9 ⇒ z = 0 and 9 + z = 18 ⇒ z = 9

Thus, z = 0 or 9.

**Ex 16.2 Class 8
Maths Question 3.**

If 24*x*is a multiple of 3, where

*x*is a digit, what is the value of

*x*?

**Solution:**

Since 24x is divisible by 3. So, the sum of its digits 2 + 4 + x = (6 + x) is

divisible by 3.

∴ (6 + x) is one of the numbers 0, 3, 6,
9, 12, 15, 18, …

But x is a digit. Therefore, (6 + x) must be equal to 6 or 9 or 12 or 15.

i.e., 6 + x = 6 or 9 or 12 or 15

⇒ x = 0 or 3 or 6 or 9

Thus, x can have any of the four different values, i.e., 0, 3, 6 or 9.

**Ex 16.2 Class 8
Maths Question 4.**

31*z*5 is a multiple of 3, where

*z*is a digit, what might be the values of

*z*?

**Solution:**

Since 31z5 is divisible by 3. So, the sum of its digits 3 + 1 + z + 5 = (9 + z)
is divisible by 3.

∴ (9 + z) is one of the numbers 0, 3, 6,
9, 12, 15, 18, …

But z is a digit. Therefore, (9 + z) must be equal to 9 or 12 or 15 or 18.

i.e., 9 + z = 9 or 12 or 15 or 18

⇒ z = 0 or 3 or 6 or 9

Thus, z can have any of the four different values, i.e., 0, 3, 6 or 9.

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