NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 (Rationalised Contents)

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 are the part of NCERT Solutions for Class 7 Maths (Rationalised Contents). Here you can find the NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5.

Ex 2.5 Class 7 Maths Question 1.

Find:
(i) 0.4 ÷ 2
(ii) 0.35 ÷ 5
(iii) 2.48 ÷ 4
(iv) 65.4 ÷ 6
(v) 651.2 ÷ 4
(vi) 14.49 ÷ 7
(vii) 3.96 ÷ 4
(viii) 0.80 ÷ 5

Solution:

Ex 2.5 Class 7 Maths Question 2.

Find:
(i) 4.8 ÷ 10
(ii) 52.5 ÷ 10
(iii) 0.7 ÷ 10
(iv) 33.1 ÷ 10
(v) 272.23 ÷ 10
(vi) 0.56 ÷ 10
(vii) 3.97 ÷ 10

Solution:
We know that when we divide a decimal number by 10, the decimal point is shifted 1 place to the left.
(i) 4.8 ÷ 10 = 0.48          (By shifting the decimal point to the left by 1 place)
(ii) 52.5 ÷ 10 = 5.25       (By shifting the decimal point to the left by 1 place)
(iii) 0.7 ÷ 10 = 0.07        (By shifting the decimal point to the left by 1 place)
(iv) 33.1 ÷ 10 = 3.31      (By shifting the decimal point to the left by 1 place)
(v) 272.23 ÷ 10 = 27.223 (By shifting the decimal point to the left by 1 place)
(vi) 0.56 ÷ 10 = 0.056    (By shifting the decimal point to the left by 1 place)
(vii) 3.97 ÷ 10 = 0.397   (By shifting the decimal point to the left by 1 place)

Ex 2.5 Class 7 Maths Question 3.

Find:
(i) 2.7 ÷ 100
(ii) 0.3 ÷ 100
(iii) 0.78 ÷ 100
(iv) 432.6 ÷ 100
(v) 23.6 ÷ 100
(vi) 98.53 ÷ 100

Solution:
We know that when we divide a decimal number by 100, the decimal point is shifted 2 places to the left.
(i) 2.7 ÷ 100 = 0.027             (By shifting the decimal point to the left by 2 places)
(ii) 0.3 ÷ 100 = 0.003            (By shifting the decimal point to the left by 2 places)
(iii) 0.78 ÷ 100 = 0.0078       (By shifting the decimal point to the left by 2 places)
(iv) 432.6 ÷ 100 = 4.326       (By shifting the decimal point to the left by 2 places)
(v) 23.6 ÷ 100 = 0.236          (By shifting the decimal point to the left by 2 places)
(vi) 98.53 ÷ 100 = 0.9853     (By shifting the decimal point to the left by 2 places)

Ex 2.5 Class 7 Maths Question 4.

Find:
(i) 7.9 ÷ 1000
(ii) 26.3 ÷ 1000
(iii) 38.53 ÷ 1000
(iv) 128.9 ÷ 1000
(v) 0.5 ÷ 1000

Solution:
We know that when we divide a decimal number by 1000, the decimal point is shifted 3 places to the left.
(i) 7.9 ÷ 1000 = 0.0079           (By shifting the decimal point to the left by 3 places)
(ii) 26.3 ÷ 1000 = 0.0263        (By shifting the decimal point to the left by 3 places)
(iii) 38.53 ÷ 1000 = 0.03853   (By shifting the decimal point to the left by 3 places)
(iv) 128.9 ÷ 1000 = 0.1289     (By shifting the decimal point to the left by 3 places)
(v) 0.5 ÷ 1000 = 0.0005           (By shifting the decimal point to the left by 3 places)

Ex 2.5 Class 7 Maths Question 5.

Find:
(i) 7 ÷ 3.5
(ii) 36 ÷ 0.2
(iii) 3.25 ÷ 0.5
(iv) 30.94 ÷ 0.7
(v) 0.5 ÷ 0.25
(vi) 7.75 ÷ 0.25
(vii) 76.5 ÷ 0.15
(viii) 37.8 ÷ 1.4
(ix) 2.73 ÷ 1.3

Solution:

Ex 2.5 Class 7 Maths Question 6.

A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?

Solution:
Since 2.4 litres of petrol is required to cover 43.2 km of distance.
∴ 1 litre of petrol will be required to cover

Hence, the required distance to be covered in 1 litre of petrol is 18 km.

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