NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 are the part of NCERT Solutions for Class 7 Maths. Here you can find the NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5.



Ex 2.5 Class 7 Maths Question 1.

Which is greater?
(i) 0.5 or 0.05
(ii) 0.7 or 0.5
(iii) 7 or 0.7
(iv) 1.37 or 1.49
(v) 2.03 or 2.30
(vi) 0.8 or 0.88

Solution:
(i) 0.5 or 0.05
Comparing the tenths place, we get 5 > 0
0.5 > 0.05

(ii) 0.7 or 0.5
Comparing the tenths place, we get 7 > 5
0.7 > 0.5

(iii) 7 or 0.7
Comparing the ones place, we get 7 > 0
7 > 0.7

(iv) 1.37 or 1.49
Comparing the tenths place, we get 3 < 4
1.37 < 1.49

(v) 2.03 or 2.30
Comparing the tenths place, we get 0 < 3
2.03 < 2.30

(vi) 0.8 or 0.88 0.80 or 0.88
Since the tenths place is the same.
Comparing the hundredth place, we get 0 < 8
0.80 < 0.88 or 0.8 < 0.88

Ex 2.5 Class 7 Maths Question 2.

Express as rupees using decimals:
(i) 7 paise
(ii) 7 rupees 7 paise
(iii) 77 rupees 77 paise
(iv) 50 paise
(v) 235 paise

Solution:
(i) Since 1 rupee = 100 paise or 1 paise = 1/100 rupees or 0.01 rupees
7 paise = 7 × 0.01 rupees = 0.07 rupees

ii) 7 rupees 7 paise = 7 rupees + 7 × 0.01 rupees
= 7 rupees + 0.07 rupees
= 7.07 rupees

(iii) 77 rupees 77 paise = 77 rupees + 77 × 0.01 rupees

= 77 rupees + 0.77 rupees
= 77.77 rupees

(iv) 50 paise = 50 × 0.01 rupees = 0.50 rupees

(v) 235 paise = 235 × 0.01 rupees = 2.35 rupees

 

Ex 2.5 Class 7 Maths Question 3.

(i) Express 5 cm in metre and kilometre
(ii) Express 35 mm in cm, m and km

Solution:
(i) 1 metre = 100 cm or 1 cm = 1/100 m = 0.01 m
1 kilometre = 1000 metre = 100 × 1000 cm
= 100000 cm or 1 cm = 1/100000 km = 0.00001 km
5 cm = 5 × 0.01 metre = 0.05 metre
5 cm = 5 × 0.00001 km = 0.00005 km
Hence, 5 cm = 0.05 m and 0.00005 km

(ii) 1 cm = 10 mm or 1 mm = 1/10 cm = 0.1 cm

1 m = 1000 mm or 1 mm = 1/1000 m = 0.001 m

and 1 km = 1000000 mm or 1 mm = 1/1000000 km = 0.000001 km
35 mm = 35 × 0.1 cm = 3.5 cm
35 mm = 35 × 0.001 m = 0.035 m
35 mm = 35 × 0.000001 km = 0.000035 km
Hence, 35 mm = 3.5 cm, 0.035 m and 0.000035 km.

 

Ex 2.5 Class 7 Maths Question 4.

Express in kg:
(i) 200 g
(ii) 3470 g
(iii) 4 kg 8 g

Solution:
(i) 200 g = 200/1000 kg          [ 1 kg = 1000 g]
               = 0.2 kg
(ii) 3470 g = 3470/10000 = 3.47 kg        [
1 kg = 1000 g]
(iii) 4 kg 8 g = 4 kg + 8/1000 kg               [
1 kg = 1000 g]
                     = 4 kg + 0.008 kg = 4.008 kg

 

Ex 2.5 Class 7 Maths Question 5.

Write the following decimal numbers in the expanded form:
(i) 20.03
(ii) 2.03
(iii) 200.03
(iv) 2.034

Solution:
(i) 20.03 = 2 × 10 + 0 × 1 + 0 × 0.1 + 3 × 0.01
(ii) 2.03 = 2 × 1 + 0 × 0.1 + 3 × 0.01
(iii) 200.03 = 2 × 100 + 0 × 10 + 0 × 1 + 0 × 0.1 + 3 × 0.01
(iv) 2.034 = 2 × 1 + 0 × 0.1 + 3 × 0.01 + 4 × 0.001

 

Ex 2.5 Class 7 Maths Question 6.

Write the place value of 2 in the following decimal numbers:
(i) 2.56
(ii) 21.37
(iii) 10.25
(iv) 9.42
(v) 63.352

Solution:
(i) The place value of 2 in 2.56 = 2 × 1 = 2
(ii) The place value of 2 in 21.37 = 2 × 10 = 20
(iii) The place value of 2 in 10.25 = 2/10 = 0.2
(iv) The place value of 2 in 9.42 = 2/100 = 0.02
(v) The place value of 2 in 63.352 = 2/1000 = 0.002

 

Ex 2.5 Class 7 Maths Question 7.

Dinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?

Solution:
Distance travelled by Dinesh from A to C via B = AB + BC
= 7.5 km + 12.7 km
= 20.2 km

Distance travelled by Ayub from A to C via D = AD + DC
= 9.3 km + 11.8 km = 21.1 km
Since, 21.1 km > 20.2 km.
Hence, Ayub travelled more distance than Dinesh.


Ex 2.5 Class 7 Maths Question 8.

Shyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?

Solution:
Weight of the fruits bought by Shyama
= 5 kg 300 g apples + 3 kg 250 g mangoes
= 5.300 kg apples + 3.250 kg mangoes
= 8.550 kg of fruits
Weight of the fruits bought by Sarala
= 4 kg 800 g oranges + 4 kg 150 g bananas
= 4.800 kg oranges + 4.150 kg bananas
= 8.950 kg of fruits
Since, 8.950 kg > 8.550 kg
Hence, Sarala bought more fruits than Shyama.

Ex 2.5 Class 7 Maths Question 9.

How much less is 28 km than 42.6 km?

Solution:
Since, 28 km < 42.6 km

     42.6 km
  – 28.0 km
  ---------------
     14.6 km
  ---------------

Hence, 28 km is less than 42.6 km by 14.6 km.


You can also like these:

NCERT Solutions for Maths Class 8

NCERT Solutions for Maths Class 9

NCERT Solutions for Maths Class 10

NCERT Solutions for Maths Class 11

NCERT Solutions for Maths Class 12

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