**NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.1****NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.2****NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.3**

**NCERT Solutions for Class 7 Maths Chapter 1 Integers Ex 1.2 ****(Rationalised Contents)**

**Ex 1.2 Class 7 Maths Question 1.**

### Find each of the following products:

**(a)** 3 × (-1)

**(b) **(-1) × 225

**(c)** (-21) × (-30)

**(d) **(-316) ×** (-1)**

**(e)** (-15) × O × (-18)

**(f)** (-12) × (-11) × (10)

**(g)** 9 x (-3) × (-6)

**(h)** (-18) × (-5) × (-4)

**(i)** (-1) × (-2) × (-3) × 4

**(j)** (-3) × (-6) × (-2) × (-1)

**(c)**

**Solution.****(a)** 3 × (-1) = – (3 × 1) = -3**(b)** (-1) × 225 = – (1 × 225) = -225**(c)** (-21) × (-30) = 21 × 30 = 630**(d)** (-316) × (-1) = 316 × 1 = 316**(e)** (-15) × 0 × (-18) = [(-15) × 0] × (-18) = 0 × (-18) = 0**(f)** (-12) × (-11) × (10) = [(-12) × (-11)] × (10)

= (132) × (10) = 1320**(g)** 9 × (-3) × (-6) = [9 × (-3)] × (-6) = (-27) × (-6) = 162**(h)** (-18) × (-5) × (-4) = [(-18) × (-5)] × (-4)

= 90 × (-4) = -360**(i)** (-1) × (-2) × (-3) × 4 = [(-1) × (-2)] × [(-3) × 4]

= (2) × (-12) = -24**(j)** (-3) × (-6) × (-2) × (-1) = [(-3) × (-6)] × [(-2) × (-1)] = (18) × (2) = 36

** **

**Ex 1.2 Class 7 Maths Question 2.**

### Verify the following:

**(a)** 18 × [7 + (-3)] = [18 × 7] + [18 × (-3)]

**(b)** (-21) × [(-4) + (-6)] = [(-21) × (-4)] + [(-21) × (-6)]

**Solution.****(a)** We have,

LHS = 18 × [7 + (-3)] = 18 × 4 = 72

RHS = [18 × 7] + [18 × (-3)] = 126 – 54 = 72

18 × [7 + (-3)] = [18 × 7] + [18 × (-3)]**(b)** We have,

LHS = (-21) × [(-4) + (-6)] = (-21) × (-4 – 6) = (-21) (-10) = 210

RHS = [(-21) × (-4) + [(-21) × (-6)] = 84 + 126 = 210

∴ (-21) × [(-4) + (-6)] = [(-21) × (-4)] + [(-21) × (-6)]

** **

**Ex 1.2 Class 7 Maths Question 3.**

**(i)** For any integer *a*, what is (-1) × *a* equal to?

**(ii)** Determine the integer whose product with (-1) is

**(a)** -22

**(b)** 37

**(c)** 0

**Solution.****(i)** For any integer *a*, (-1) × *a* = -*a*.**(ii) **We know that the product of any integer and (-1) is the additive inverse of the integer. The integer whose product with (-1) is**(a)** -22 is the additive inverse of -22, i.e., 22.**(b)** 37 is the additive inverse of 37, i.e., -37.**(c)** 0 is the additive inverse of 0, i.e., 0.

** **

**Ex 1.2 Class 7 Maths Question 4.**

### Starting from (-1) × 5, write various products showing some pattern to show (-1) × (-1) = 1.

**Solution.**(-1) × 5 = -5

(-1) × 4 = -4 = [-5 – (-1)] = -5 + 1

(-1) × 3 = -3 = [-4 – (-1)] = -4 + 1

(-1) × 2 = -2 = [-3 – (-1)] = -3 + 1

(-1) × 1 = -1 = [-2 – (-1)] = -2 + 1

(-1) × 0 = 0 = [-1 – (-1)] = -1 + 1

(-1) × (-1) = [0 – (-1)] = 0 + 1 = 1

**Related Links:**

**NCERT Solutions for Maths Class 8**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**