**NCERT Solutions for Class 8 Maths Chapter 6 Squares
and Square Roots Ex 6.2**

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square
Roots Ex 6.2 are the part of NCERT Solutions for Class 8 Maths. Here you can
find the NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots
Ex 6.2**.**

**Ex 6.2 Class 8 Maths Question 1.**

Find the
square of the following numbers.**(i)**32

**(ii)**35

**(iii)**86

**(iv)**93

**(v)**71

**(vi)**46

**Solution:**

**(i)** 32^{2} =
(30 + 2)^{2}

= 30 (30 + 2) + 2 (30 + 2)

= 30^{2} + 30 × 2 + 2 ×
30 + 2^{2}

= 900 + 60 + 60 + 4 = 1024

**(ii)** (35)^{2} = (30 + 5)^{2}

= 30 (30 + 5) + 5 (30 + 5)

= 30^{2} +
30 × 5 + 5 × 30 + 5^{2}

= 900 + 150 + 150 + 25 =
1225

**(iii)** (86)^{2} = (80 + 6)^{2}

= 80 (80 + 6) + 6 (80 + 6)

= 80^{2} + 80
× 6 + 6 ×
80 + 6^{2}

= 6400 + 480 + 480 + 36
= 7396

**(iv)** (93)^{2} = (90 + 3)^{2}

= 90 (90 + 3) + 3 (90 + 3)

= 90^{2} +
90 × 3 + 3 × 90 + 3^{2}

= 8100 + 270 + 270 + 9 =
8649

**(v)** (71)^{2} = (70 + 1)^{2}

= 70 (70 +1) +1 (70 +1)

= 70^{2} + 70
× 1 + 1 ×
70 + 1^{2}

= 4900 + 70 + 70 + 1 =
5041

**
(vi)** (46)

^{2}= (40 + 6)

^{2}

= 40 (40 + 6) + 6 (40 + 6)

= 40^{2} +
40 × 6 + 6 × 40 + 6^{2}

= 1600 + 240 + 240 + 36
= 2116

**Ex 6.2 Class 8
Maths Question 2.**

Write a Pythagorean triplet whose one member is:**(i)**6

**(ii)**14

**(iii)**16

**(iv)**18

**Solution:**

**(i)** Put
m = 3 in 2m, m^{2} – 1, m^{2} + 1, we get

2m = 6, m^{2} – 1 = 3^{2} – 1 = 9 – 1 = 8 and m^{2} +
1 = 9 + 1 = 10

Thus, 6, 8 and 10 are Pythagorean triplets.

**(ii)** Put m = 7 in 2m, m^{2} –
1, m^{2} + 1, we get

2m = 14, m^{2} – 1 = 7^{2} – 1 = 49 – 1 = 48 and m^{2} +
1 = 7^{2} + 1 = 49 + 1 = 50

Thus, 14, 48 and 50 are Pythagorean triplets.

**(iii)** Put m = 8 in 2m, m^{2} –
1, m^{2} + 1, we get

2m = 16, m^{2} – 1 = 8^{2} – 1 = 64 – 1 = 63 and m^{2} +
1 = 8^{2} + 1 = 64 + 1 = 65

Thus, 16, 63 and 65 are Pythagorean triplets.

**(iv)** Put m = 9 in 2m, m^{2} –
1, m^{2} + 1, we get

2m = 18, m^{2} – 1 = 9^{2} – 1 = 81 – 1 = 80 and m^{2
}+ 1 = 9^{2} + 1 = 81 + 1 = 82

Thus, 18, 80 and 82 are Pythagorean triplets.

**You can also like these:**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**

**NCERT Solutions for Maths Class 11**