## NCERT Solutions for Class 8 Maths Chapter 6 Cubes and Cube Roots Ex 6.2

NCERT Solutions for Class 8 Maths Chapter 6 Cubes and Cube
Roots Ex 6.2 are the part of NCERT Solutions for Class 8 Maths (Rationalised Contents). Here you can
find the NCERT Solutions for Class 8 Maths Chapter 6 Cubes and Cube Roots
Ex 6.2**.**

### Ex 6.2 Class 8 Maths Question 1.

### Find the cube root of each of the following numbers by prime factorisation method.

(i) 64

(ii) 512

(iii) 10648

(iv) 27000

(v) 15625

(vi) 13824

(vii) 110592

(viii) 46656

(ix) 175616

(x) 91125

Solution:

### Ex 6.2 Class 8 Maths Question 2.

### State true or false.

(i) Cube of any odd number is even.

(ii) A perfect cube does not end with two zeros.

(iii) If the square of a number ends with 5, then its cube ends with 25.

(iv) There is no perfect cube which ends with 8.

(v) The cube of a two digit number may be a three digit number.

(vi) The cube of a two digit number may have seven or more digits.

(vii) The cube of a single digit number may be a single digit number.

Solution:

(i) False – Because the cube of any odd number is always odd, e.g., (5)^{3} = 125

(ii) True – Because a perfect cube does not end with two zeros.

(iii) True – Because if the square of a number ends with 5, then its cube ends with 25, e.g., (5)^{2} = 25 and (5)^{3} = 625

(iv) False – Because (12)^{3} = 1728 (ends with 8)

(v) False – Because (10)^{3} = 1000 (4-digit number)

(vi) False – Because (99)^{3} = 970299 (6-digit number)

(vii) True – Because (2)^{3} = 8 (1-digit number)

Related Links:

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**

**NCERT Solutions for Maths Class 11**