NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.1
NCERT Solutions for Class
8 Maths Chapter 2 Linear
Equations in One Variable Ex 2.1 are the
part of NCERT Solutions for Class 8 Maths. Here you can find the NCERT
Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable
Ex 2.1.
Ex 2.1 Class 8 Maths Question 1.
Solve the equation: x – 2 = 7Solution:
Given: x – 2 = 7
⇒ x – 2 + 2 = 7 + 2 (Adding 2 on both sides)
⇒ x = 9
Thus, x = 9 is the required solution.
Ex 2.1 Class 8 Maths Question 2.
Solve the equation: y + 3 = 10Solution:
Given: y + 3 = 10
⇒ y + 3 – 3 = 10 – 3 (Subtracting 3 from both sides)
⇒ y = 7
Thus, y = 7 is the required solution.
Ex 2.1 Class 8 Maths Question 3.
Solve the equation: 6 = z + 2Solution:
Given: 6 = z + 2
⇒ 6 – 2 = z + 2 – 2 (Subtracting 2 from both sides)
⇒ 4 = z
Thus, z = 4 is the required solution.
Ex 2.1 Class 8 Maths Question 4.
Solve the equations: 3/7 + x = 17/7Solution:
Ex 2.1 Class 8 Maths Question 5.
Solve the equation: 6x = 12Solution:
Given: 6x = 12
⇒ 6x ÷ 6 = 12 ÷ 6 (Dividing each side by 6)
⇒ x = 2
Thus, x = 2 is the required solution.
Ex 2.1 Class 8 Maths Question 6.
Solve the equation: t/5 = 10Solution:
Given: t/5 = 10
⇒ t/5 × 5 = 10 × 5 (Multiplying both sides by 5)
⇒ t = 50
Thus, t = 50 is the required solution.
Ex 2.1 Class 8 Maths Question 7.
Solve the equation: 2x/3 = 18Solution:
Given: 2x/3 = 18
⇒ 2x/3 × 3 = 18 ×
3 (Multiplying both sides by 3)
⇒ 2x = 54
⇒ 2x ÷ 2 = 54 ÷ 2 (Dividing both sides by 2)
⇒ x = 27
Thus, x = 27 is the required solution.
Ex 2.1 Class 8 Maths Question 8.
Solve the equation: 1.6 = y/1.5Solution:
Given: 1.6 = y/1.5
⇒ 1.6 × 1.5 = y/1.5 × 1.5 (Multiplying both sides by 1.5)
⇒ 2.40 = y
Thus, y = 2.4 is the required solution.
Ex 2.1 Class 8 Maths Question 9.
Solve the equation: 7x – 9 = 16Solution:
Given: 7x – 9 = 16
⇒ 7x – 9 + 9 = 16 + 9 (Adding 9 to both sides)
⇒ 7x = 25
⇒ 7x ÷ 7 = 25 ÷ 7 (Dividing both sides by 7)
⇒ x = 25/7
Thus, x = 25/7 is the
required solution.
Ex 2.1 Class 8 Maths Question 10.
Solve the equation: 14y – 8 = 13Solution:
Given: 14y – 8 = 13
⇒ 14y – 8 + 8 = 13 + 8 (Adding 8 to both sides)
⇒ 14y = 21
⇒ 14y ÷ 14 = 21 ÷ 14 (Dividing both sides by 14)
⇒ y = 21/14
⇒ y = 3/2
Thus, y = 3/2 is the
required solution.
Ex 2.1 Class 8 Maths Question 11.
Solve the equation: 17 + 6p = 9Solution:
Given: 17 + 6p = 9
⇒ 17 – 17 + 6p = 9 – 17 (Subtracting 17 from both sides)
⇒ 6p = -8
⇒ 6p ÷ 6 = -8 ÷ 6 (Dividing both sides by
6)
⇒ p = −8/6
⇒ p = −4/3
Thus, p = −4/3 is the required solution.
Ex 2.1 Class 8 Maths Question 12.
Solve the equation: x/3 + 1 = 7/15Solution:
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