**NCERT Solutions for Class 8 Maths Chapter 2 Linear
Equations in One Variable Ex 2.1**

NCERT Solutions for Class
8 Maths **Chapter 2 Linear
Equations in One Variable Ex 2.1** are the
part of NCERT Solutions for Class 8 Maths. Here you can find the NCERT
Solutions for Class 8 Maths **Chapter 2 Linear Equations in One Variable
Ex 2.1**.

**Ex 2.1 Class 8 Maths Question 1.**

Solve the equation: x – 2 = 7**Solution:****
**Given: x – 2 = 7

⇒ x – 2 + 2 = 7 + 2 (Adding 2 on both sides)

⇒ x = 9

Thus, x = 9 is the required solution.

**Ex 2.1 Class 8 Maths Question 2.**

Solve the equation: y + 3 = 10

**Solution:****
**Given: y + 3 = 10

⇒ y + 3 – 3 = 10 – 3 (Subtracting 3 from both sides)

⇒ y = 7

Thus, y = 7 is the required solution.

**Ex 2.1 Class 8 Maths Question 3.**

Solve the equation: 6 = z + 2**Solution:
**Given: 6 = z + 2

⇒ 6 – 2 = z + 2 – 2 (Subtracting 2 from both sides)

⇒ 4 = z

Thus, z = 4 is the required solution.

**Ex 2.1 Class 8 Maths Question 4.**

Solve the equations: 3/7 + x = 17/7**Solution:**

**Ex 2.1 Class 8 Maths Question 5.**

Solve the equation: 6x = 12**Solution:
**Given: 6x = 12

⇒ 6x ÷ 6 = 12 ÷ 6 (Dividing each side by 6)

⇒ x = 2

Thus, x = 2 is the required solution.

**Ex
2.1 Class 8 Maths Question 6.**

Solve the equation: t/5 = 10**Solution:
**Given: t/5 = 10

⇒ t/5 × 5 = 10 × 5 (Multiplying both sides by 5)

⇒ t = 50

Thus, t = 50 is the required solution.

**Ex
2.1 Class 8 Maths Question 7.**

Solve the equation: 2x/3 = 18**Solution:
**Given: 2x/3 = 18

⇒ 2x/3 × 3 = 18 × 3 (Multiplying both sides by 3)

⇒ 2x = 54

⇒ 2x ÷ 2 = 54 ÷ 2 (Dividing both sides by 2)

⇒ x = 27

Thus, x = 27 is the required solution.

**Ex
2.1 Class 8 Maths Question 8.**

Solve the equation: 1.6 = y/1.5**Solution:
**Given: 1.6 = y/1.5

⇒ 1.6 × 1.5 = y/1.5 × 1.5 (Multiplying both sides by 1.5)

⇒ 2.40 = y

Thus, y = 2.4 is the required solution.

**Ex
2.1 Class 8 Maths Question 9.**

Solve the equation: 7x – 9 = 16**Solution:
**Given: 7x – 9 = 16

⇒ 7x – 9 + 9 = 16 + 9 (Adding 9 to both sides)

⇒ 7x = 25

⇒ 7x ÷ 7 = 25 ÷ 7 (Dividing both sides by 7)

⇒ x = 25/7

Thus, x = 25/7 is the required solution.

**Ex
2.1 Class 8 Maths Question 10.**

Solve the equation: 14y – 8 = 13**Solution:
**Given: 14y – 8 = 13

⇒ 14y – 8 + 8 = 13 + 8 (Adding 8 to both sides)

⇒ 14y = 21

⇒ 14y ÷ 14 = 21 ÷ 14 (Dividing both sides by 14)

⇒ y = 21/14

⇒ y = 3/2

Thus, y = 3/2 is the required solution.

**Ex
2.1 Class 8 Maths Question 11.**

Solve the equation: 17 + 6p = 9**Solution:
**Given: 17 + 6p = 9

⇒ 17 – 17 + 6p = 9 – 17 (Subtracting 17 from both sides)

⇒ 6p = -8

⇒ 6p ÷ 6 = -8 ÷ 6 (Dividing both sides by 6)

⇒ p = −8/6

⇒ p = −4/3

Thus, p = −4/3 is the required solution.

**Ex
2.1 Class 8 Maths Question 12.**

Solve the equation: x/3 + 1
= 7/15**Solution:**

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