**NCERT Solutions for Class 9
Maths Chapter 11 Constructions Ex 11.2**

NCERT Solutions for Class
9 Maths Chapter 11 Constructions Ex 11.2 are the part
of NCERT Solutions for Class 9 Maths. Here you can find the NCERT Solutions for
Chapter 11 Constructions Ex 11.2.

**Ex 11.2 Class 9 Maths Question 1.****
**Construct a ∆ABC in which BC = 7
cm, ∠B = 75° and AB + AC = 13 cm.

**Solution:****
Steps of Construction:
**Step I : Draw a ray BX.

Step II : Along BX, cut off a line segment BC = 7 cm.

Step III : At B, construct ∠CBY = 75°.

Step IV : From the ray BY, cut off BD = 13 cm (= AB + AC).

Step V : Join DC.

Step VI : Draw a perpendicular bisector of CD which meets BD at A.

Step VII: Join AC.

**Ex 11.2 Class 9 Maths Question 2.****
**Construct a ∆ABC in which BC = 8
cm, ∠B = 45° and AB – AC = 3.5 cm.

**Solution:****
Steps of Construction:
**Step I : Draw a ray BX.

Step II : Along BX, cut off a line segment BC = 8 cm.

Step III : At B, construct ∠CBY = 45°.

Step IV : From BY, cut off BD = 3.5 cm (= AB – AC).

Step V : Join DC.

Step VI : Draw PQ, perpendicular bisector of DC, which intersects BY at A.

Step VII: Join AC.

**Ex 11.2 Class 9 Maths Question 3.****
**Construct a ∆ABC in which QR = 6
cm, ∠Q = 60° and PR – PQ = 2 cm.

**Solution:****
Steps of Construction:
**Step I : Draw a ray QX.

Step II : Along QX, cut off a line segment QR = 6 cm.

Step III : Construct a line YQY’ such that ∠RQY = 60°.

Step IV : Cut off QS = 2 cm (= PR – PQ) on QY’.

Step V : Join SR.

Step VI : Draw MN, perpendicular bisector of SR, which intersects QY at P.

Step VII: Join PR.

**Ex 11.2 Class 9 Maths Question 4.****
**Construct a ∆XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm.

**Solution:****
Steps of Construction:
**Step I : Draw a line segment AB =
11 cm = (XY + YZ + ZX)

Step II : Construct ∠BAP = 30°

Step III : Construct ∠ABQ = 90°

Step IV : Draw AR, the bisector of ∠BAP.

Step V : Draw BS, the bisector of ∠ABQ. Let AR and BS intersect at X.

Step VI : Draw perpendicular bisector of AX, which intersects AB at Y.

Step VII: Draw perpendicular bisector of XB, which intersects AB at Z.

Step VIII: Join XY and XZ.

**Ex
11.2 Class 9 Maths Question 5.
**Construct a right triangle whose base is 12 cm and
sum of its hypotenuse and other side is 18 cm.

**Solution:
Steps of Construction:
**Step I : Draw BC = 12 cm.

Step II : At B, construct ∠CBY = 90°.

Step III : Along BY, cut off a line segment BX = 18 cm.

Step IV : Join CX.

Step V : Draw PQ, the perpendicular bisector of CX, which meets BX at A.

Step VI : Join AC.

Thus, ∆ABC is the required triangle.

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