**NCERT Solutions for Class 9
Maths Chapter 10 **Heron’s Formula** Ex 10.1**

NCERT Solutions for Class
9 Maths Chapter 10 Heron’s Formula Ex 10.1 are the part
of NCERT Solutions for Class 9 Maths. In this post, you will find the NCERT Solutions for
Chapter 10 Heron’s Formula Ex 10.1.

**Ex 10.1 Class 9 Maths Question 1.**A traffic signal board, indicating ‘SCHOOL AHEAD’, is an equilateral triangle with side a. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board?

**Solution:**We know that, an equilateral triangle has equal sides. So, all sides are equal to a.

Perimeter of the triangle = 180 cm

⇒ a + a + a = 180

⇒ 3a = 180

⇒ a = 60 cm

Now, semi-perimeter (s) = (a + a + a)/2 (∵ 2s = a + b + c)

s = 180/2 = 90 cm

**Ex 10.1 Class 9 Maths Question 2.**The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see Fig.). The advertisements yield an earning of ₹ 5000 per m

^{2 }per year. A company hired one of its walls for 3 months. How much rent did it pay?

**Solution:**The lengths of the sides of the triangular walls are 122 m, 22 m and 120 m.

**Ex 10.1 Class 9 Maths Question 3.**

There is a slide in a park. One of its side walls has been painted in some colour with a message ‘KEEP THE PARK GREEN AND CLEAN” (see figure). If the sides of the wall are 15 m, 11 m and 6 m, find the area painted in colour.

**Solution:**

**Ex 10.1 Class 9 Maths Question 4.**Find the area of a triangle two sides of which are 18 cm and 10 cm and the perimeter is 42 cm.

**Solution:**Let the sides of the triangle be a =18 cm, b = 10 cm and c = x cm

Since, perimeter of the triangle = 42 cm

∴ 18 cm + 10 cm + x cm = 42

x = [42 – (18 + 10) cm = 14 cm

Now, semi-perimeter, s = 42/2 = 21 cm

Thus, the required area of the triangle is 21√11 cm^{2}.^{}

**Ex 10.1 Class 9 Maths Question 5.**Sides of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area.

**Solution:**Let the sides of the triangle be a = 12x cm, b = 17x cm and c = 25x cm

Perimeter of the triangle = 540 cm

Now, 12x + 17x + 25x = 540

⇒ 54x = 540 ⇒ x = 10

∴ a = (12 × 10) cm = 120 cm,

b = (17 × 10) cm = 170 cm

and c = (25 × 10) cm = 250 cm

Now, semi-perimeter, s = 540/2 = 270 cm

**Ex 10.1 Class 9 Maths Question 6.**

An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of the triangle.

**Solution:**Let the sides of an isosceles triangle be a = 12 cm, b = 12 cm and c = x cm

Since, perimeter of the triangle = 30 cm

∴ 12 cm + 12 cm + x cm = 30 cm

⇒ x = (30 – 24) = 6 cm

Now, semi-perimeter, s = 30/2 =15 cm

Thus, the required area of the triangle is 9√15 cm^{2}.

**Related Links:**

**NCERT Solutions for Maths Class 10**

**NCERT Solutions for Maths Class 11**