NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.4
NCERT Solutions for Class
9 Maths Chapter 1 Number Systems Ex 1.4 are the part of NCERT Solutions for
Class 9 Maths. Here you can find the NCERT Solutions for Class 9 Maths Chapter
1 Number System Ex 1.4.
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.1
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.2
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.3
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.4
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.5
- NCERT Solutions for Class 9 Maths Chapter 1 Number Systems Ex 1.6
Ex 1.4 Class 9 Maths Question 1.
Visualise
3.765 on the number line, using successive magnification.
Solution:
We know that, 3.765 lies between 3 and 4. So, let us
divide the part of the number line between 3 and 4 into 10 equal parts and look
at the portion between 3.7 and 3.8 through a magnifying glass. Now, 3.765 lies
between 3.7 and 3.8 [Fig. (i)]. Now, we imagine to divide this again into ten
equal parts. The first mark will represent 3.71, the second mark 3.72, the
third 3.73 and so on. To see this clearly, we magnify this as shown in [Fig.
(ii)].
Again 3.765 lies between 3.76 and 3.77 [Fig. (ii)].
So, let us magnify this portion of the number line [Fig. (iii)] and imagine to
divide it again into ten equal parts [Fig. (iii)]. Here, we can visualise that
3.761 is the first mark and 3.765 is the 5th mark in these subdivisions. We
call this process of visualisation of representation of numbers on the number
line through a magnifying glass as the process of successive magnification.
So, we get seen that it is possible by sufficient successive magnifications of visualise the position (or representation) of a real number with a terminating decimal expansion on the number line.
Ex 1.4 Class 9 Maths Question
2.
Visualise
4.2626…. on the number line, up to 4 decimal
places.
Solution:
We adopt process by successive magnification and successively
decrease the lengths of the portion of the number line in which 4.2626… is
located. Since 4.2626… is located between 4 and 5 and is divided
into 10 equal parts [Fig. (i)]. Further, we locate 4.26 between 4.2 and 4.3
[Fig. (ii)].
To
get more accurate visualisation of the representation, we divide this portion
into 10 equal parts and use a magnifying glass to visualise that 4.2626… lies
between 4.26 and 4.27. To visualise 4.2626… more clearly, we divide the portion again
between 4.26 and 4.27 into 10 equal parts and visualise the representation of
4.2626… between
4.262 and 4.263 [Fig. (iii)].
Now,
for a much better visualisation between 4.262 and 4.263, we again divide this
portion into 10 equal parts [Fig. (iv)].