**Perimeter of a
Square**

We know that the square is a plane
figure or two-dimensional figure. All the sides of a square are equal and all
the angles of a square measure 90°.

The **perimeter **of a closed
two-dimensional figure is the length of its boundary. The units of measurement
of perimeter are the same as that of length, i.e. cm, m or km.

To find the perimeter of a square,
we add the measures of all its sides.

Let we have to find the perimeter of a given square ABCD.

Perimeter of the square ABCD = AB + BC + CD + DA

= AB + AB + AB + AB
(Since, AB = BC = CD = DA)

= 4 AB

= 4 × side

Thus, the **perimeter of a square
= 4 **×** side**

If the length of each side of the
square is *s*, then

**Perimeter
of a square =** **4 **×** s**

**Perimeter of a Square
Formula**

**Perimeter
of a square = 4 **×** s**

Where *s* is the length of each
side of the square.

**Perimeter of a Square
Example**

**Example 1: **Find
the perimeter of a square, whose each side measures 6.5 cm.

**Solution: **Given:
side of the square, s = 6.5 cm

Perimeter of a square = 4 × s

= 4 ×
6.5 cm

= 26 cm

**Example 2: **A
square plot is 75 m long. Find the length of the wire required to fence

all around it 4 times.

**Solution: **Given:
length of the square plot, s = 75 m

Length of the wire to fence it one
time = Perimeter of the square plot

= 4 × s

= 4 × 75 m

= 300 m

Length of the wire required to fence
the square plot 4 times = 4 × 300 m = 1200 m

Hence, the total length of the wire
required to fence the square plot is 1200 m.

**Example 3: **Aman takes 20 rounds of a square park which is 60 m long. Find
the total distance covered by him in kilometres.

**Solution: **Given: length of the park, s = 60 m

Distance covered by Aman
in 1 round = Perimeter of the park

= 4 × s

= 4 × 60 m

= 240 m

Total distance covered
by Aman in 20 rounds = 20 × 240 m = 4800 m

Thus, the total distance
covered in kilometres = 4800/1000 km

(Since 1 km = 1000 m)

= 4.8 km

**Example 4: **If the perimeter of a square field is 340 m, find the measure of
each side of the square field.

**Solution: **Given: perimeter of the square
field = 340 m

We know that,

Perimeter of a square = 4 × s

340 m = 4 × s

s = 340/4 = 85 m

Hence, the measure of
each side of the square field is 85 m.

**Example 5: **Each
side of a square photo frame measures 46 cm. If its border is 3 cm

wide, then find the perimeter of the
picture.

**Solution: **Given:
Side of the photo frame = 46 cm

Each side of the picture = 46 cm – (3
cm + 3 cm) = 40 cm

Thus, the perimeter of the picture = 4
× s

= 4 × 40

= 160 cm

Hence, the perimeter of the picture is 160 cm.