**Area
of a Rectangle**

Let us follow the square grid sheet method to
find the area of a rectangle.

Consider
a rectangle of length 5 cm and breadth 3 cm. Draw this rectangle on a square
grid sheet.

Count the number of squares that the rectangle covers. There are 15 squares. So, the area of a rectangle of sides 5 cm and 3 cm is 15 sq. cm.

Since
15 = 5 × 3, therefore the product of the length and the breadth of the
rectangle is equal to its area.

From
this verified result, we can conclude that

**Area of a rectangle **= **length
**× **breadth**

**Area of a Rectangle Formula**

**Area of a rectangle **= **length **× **breadth**

**Area of a Rectangle Example**

**Example
1: **Find
the area of a rectangle whose length is 60 cm and breadth is 40 cm.

**Solution:** Given: Length = 60 cm and breadth =
40 cm

We
know that,

Area
of a rectangle = length × breadth

= 60 × 40 =
2400 sq. cm

**Example 2: **The perimeter of a rectangle is 48
cm. If the length of the rectangle is 14 cm, then find the area of the
rectangle.

**Solution:**
Given: Length of the rectangle = 14 cm and perimeter of the rectangle = 48 cm

We know that,

Perimeter of a rectangle = 2(length +
breadth)

48 =
2(14 + breadth)

24 = 14
+ breadth

Breadth = 24 – 14
= 10 cm

Area of a rectangle = length × breadth

= 14 × 10 = 140 sq. cm

**Example 3:** The area of a rectangular park is
240 sq. m. If its length is 16 m, find the breadth.

**Solution:**
The area of the park = 240 sq. m

The length of the park = 16 m

The breadth of the park = ?

The area of the park = length ×
breadth

240 = 16 ×
breadth

So, breadth = 240/16 = 15 m

**Example 4: **How
many rectangular tiles of length 20 cm and breadth 10 cm will be

required to cover a rectangular floor whose
length and breadth are 8 m and 5 m, respectively?

**Solution: **Here,
length of the floor = 8 m = 800 cm

Breadth of the floor = 5 m = 500 cm

Area of the floor = 800 cm × 500 cm = 400000
cm^{2}

Area of 1 tile = 20 cm × 10 cm = 200
cm^{2}

Thus, the number of tiles required =
Area of the floor/Area of 1 tile

= 400000/200

= 2000 tiles

Hence, the number of tiles required is
2000.