Hello Students. In this post, you will find the complete** ****NCERT Solutions for Maths Class 12 Exercise 9.5**.

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**NCERT Solutions for Maths Class 12 Exercise 9.1**

**NCERT Solutions for Maths Class 12 Exercise 9.2**

**NCERT Solutions for Maths Class 12 Exercise 9.3**

**NCERT Solutions for Maths Class 12 Exercise 9.4**

**NCERT Solutions for Maths Class 12 Exercise 9.5**

**Find the general solution of the following differential equations in Q.1 to 12.**

**Maths Class 12 Ex 9.5 Question 1.**

**Solution:**

The given equation is a linear differential equation of the form;

Here, P = 2 and Q = sin x

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 2.**

**Solution:**

The given equation is a linear differential equation of the form;

Here, P = 3 and Q = *e ^{-2x}*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 3.**

**Solution:**

The given equation is a linear differential equation of the form;

Here, P = 1/*x* and Q = *x*^{2}

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 4.**

**Solution:**

The given equation is a linear differential equation of the form;

Here, P = sec *x* and Q = tan *x*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 5.**

**Solution:**

The given differential equation can be written as *dy*/*dx* + (sec^{2} *x*) *y *= tan *x* sec^{2} *x*

This differential equation is of the form;

Here, P = sec^{2} *x* and Q = tan *x* sec^{2} *x*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 6.**

**Solution:**

The given differential equation can be written as *dy*/*dx* + 2*y*/*x *= *x* log *x*

This differential equation is of the form;

Here, P = 2/*x* and Q = *x* log *x*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 7.**

**Solution:**

The given differential equation is

This differential equation is of the form;

Here, P = 2/(*x* log *x*) and Q = 2/*x*^{2}

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 8.**

(1 + *x*²) *dy* + 2*xy dx* = cot *x dx* (*x* ≠ 0)

**Solution:**

The given differential equation is (1 + *x*²) *dy* + 2*xy dx* = cot *x dx* (*x* ≠ 0)

Here, P = 2*x*/(1 + *x*^{2}) and Q = (cot *x*)/(1 + *x*^{2})

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 9.**

*x dy*/*dx* + *y* – *x* + *xy* cot *x* = 0 (*x* ≠ 0)

**Solution:**

The given differential equation is

Here, P = 1/*x* + cot *x* and Q = 1

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 10.**

(*x* + *y*) *dy*/*dx* = 1

**Solution:**

The given differential equation is (*x* + *y*) *dy*/*dx* = 1

Or *dx*/*dy* *–* *x* = *y*

This differential equation is of the form *dx*/*dy* + *Px* = *Q*;

Here, P = *–*1 and Q = *y*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

**Maths Class 12 Ex 9.5 Question 11.**

*y dx* + (*x* – *y*^{2}) *dy* = 0

**Solution:**

The given differential equation is *y dx* + (*x* – *y*^{2}) *dy* = 0

Or *dx*/*dy* + *x*/*y* = *y*

This differential equation is of the form *dx*/*dy* + *Px* = *Q*;

Here, P = 1/*y* and Q = *y*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

**Maths Class 12 Ex 9.5 Question 12.**

(*x* + 3*y*^{2}) *dy*/*dx* = *y* (*y* > 0)

**Solution:**

The given differential equation is

*dx*/

*dy*+

*Px*=

*Q*;

Here, P = *–*1/*y* and Q = 3*y*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given differential equation.

**For each of the following Questions 13 to 15, find a particular solution satisfying the given condition:**

**Maths Class 12 Ex 9.5 Question 13.**

**Solution:**

The given differential equation is

This differential equation is of the form;

Here, P = 2 tan *x *and Q = sin *x*

Thus, the solution of the given differential equation is

This is the required particular solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 14.**

**Solution:**

The given differential equation is

Thus, the solution of the given differential equation is

This is the required particular solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 15.**

**Solution:**

The given differential equation is

This differential equation is of the form;

Here, P = –3 cot *x *and Q = sin 2*x*

Thus, the solution of the given differential equation is

This is the required particular solution of the given differential equation.

**Maths Class 12 Ex 9.5 Question 16.**

Find the equation of the curve passing through the origin given that the slope of the tangent to the curve at any point (*x*, *y*) is equal to the sum of the coordinates of the point.

**Solution:**

The slope of the a tangent to a curve is given by *dy*/*dx*.

This differential equation is of the form;

Here, P = –1 and Q = *x*

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

This is the required general solution of the given curve.

**Maths Class 12 Ex 9.5 Question 17.**

Find the equation of the curve passing through the point (0, 2) given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.

**Solution:**

The slope of the a tangent to a curve is given by *dy*/*dx*.

Now, from the given condition, we get

This differential equation is of the form;

Here, P = –1 and Q = *x *– 5

Now, the integrating factor (I.F.) is

Thus, the solution of the given differential equation is

**Maths Class 12 Ex 9.5 Question 18.**

The integrating factor of the differential equationis

(A) *e*^{-x}

(B) *e*^{-y}

(C) 1/*x*

(D) *x*

**Solution:**

The given differential equation is

This differential equation is of the form;

Here, P = –1/*x *and Q = 2*x*

Thus, the integrating factor is

**Maths Class 12 Ex 9.5 Question 19.**

The integrating factor of the differential equation(-1 < *y* < 1) is

**Solution:**

The given differential equation can be written as

Thus, the integrating factor is

Hence, the correct answer is option (D).

**Related Links:**

**NCERT Solutions for Maths Class 12 Exercise 9.1**

**NCERT Solutions for Maths Class 12 Exercise 9.2**