**NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4**

NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 are the part of NCERT Solutions for
Class 6 Maths. Here you can find the NCERT Solutions for Class 6 Maths Chapter
14 Practical Geometry Ex 14.4.

**NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.5****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.6**

**Ex
14.4 Class 6 Maths Question 1.**

Draw any line segment AB. Make any point M on it. Through M, draw a
perpendicular to AB. (Use ruler
and compasses)**Solution:
**Step 1: Draw a line segment AB of any suitable measure and mark any point M
on it.

Step 2: Put the needle of the compass at M and draw an arc of suitable radius such that it intersects AB at P and Q.

Step 4: Join M and C.

Thus, MC is the perpendicular to AB.

**Ex
14.4 Class 6 Maths Question 2.**

Draw any line segment PQ. Take any point R not on it. Through R, draw a
perpendicular to PQ. (Use ruler
and set-square).**Solution:
**Step 1: Draw a line segment PQ and take a point R on it.

Step 2: Place a set square on PQ such that one side of set square is along PQ and the other side is at right angle through R as shown below.

Step 4: Hold the set square fix and draw the perpendicular line through point R.

**Ex 14.4 Class 6 Maths Question 3.**

Draw a line *l*and a point X on it. Through X, draw a line segment XY perpendicular to

*l*. Now draw a perpendicular to XY at Y. (Use ruler and compasses)

**Solution:****
**Step 1: Draw a line l and take a
point X on it.

Step 2: Draw an arc with centre X and with suitable radius to intersect the line l at two points P and Q.

Step 4: Join XM and produce it to Y.

Step 5: With Y as centre and a suitable radius, draw an arc to intersect XY at two points R and S.

Step 6: With R and S as centres and a radius greater than YR, draw two arcs to intersect each other at point A.

Step 7: Join Y and A. Thus, YA ⊥ XY.

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