**NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2**

NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 are the part of NCERT Solutions for
Class 6 Maths. Here you can find the NCERT Solutions for Class 6 Maths Chapter
14 Practical Geometry Ex 14.2.

**NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.5****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.6**

**Ex
14.2 Class 6 Maths Question 1.**

Draw a line segment of length 7.3 cm using a ruler.**Solution:
**Step 1: Mark a point P.

Step 2: Place the 0 mark of the ruler against the point P.

Step 3: Mark a point Q at a distance of 7.3 cm from P.

Step 4: Join P and Q.

Thus, PQ is the required line segment of length 7.3 cm.

**Ex
14.2 Class 6 Maths Question 2.**

Construct a line segment of length 5.6 cm using
ruler and compasses.**Solution:
**Step 1: Draw a line

*l*of any suitable length.

Step 2: Place the needle of the compasses on the zero mark of the ruler and open it up to 5.6 cm mark.

Step 3: Place the needle at any point A at the line

*l*and draw an arc to cut

*l*at B.

Thus, AB is the required line segment of length 5.6 cm.

**Ex 14.2 Class 6 Maths Question 3.**

Construct AB of length 7.8 cm. From this, cut off AC of length 4.7 cm. Measure BC.**Solution:****
**Given that AB = 7.8 cm and AC = 4.7 cm.

Step 1: Place zero mark of the ruler at A.

Step 2: Mark a point B at a distance of 7.8 cm from A.

Step 3: Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.

Step 4: On measuring the length of BC, we find that BC = 3.1 cm.

**Ex
14.2 Class 6 Maths Question 4.**

Given AB of length
3.9 cm. Construct PQ such that
the length of PQ is twice
that of AB. Verify by
measurement.(

**Hint:**Construct PX such that the length of PX = length of AB; then cut off XQ such that XQ also has the length of AB.

**Solution:
**Step 1: Draw a line

*l*of any suitable length.

Step 2: Draw AB = 3.9 cm.

Step 3: From the line, construct PX = AB = 3.9 cm.

Step 4: Again construct XQ = AB = 3.9 cm

**Verification:**PX + XQ = AB + AB

Thus, 2AB = PQ

**Ex 14.2 Class 6 Maths Question 5.**

Given AB of length 7.3 cm and CD of length 3.4 cm, construct a line
segment XY such that
the length of XY is equal to the difference between the length of AB and CD. Verify
the measurement.**Solution:****
**Step 1: Construct AB = 7.3 cm and CD = 3.4 cm.

Step 2: Take a point P on the given line l.

Step 3: Construct XZ such that XZ = AB = 7.3 cm.

Step 4: Construct ZY = CD = 3.4 cm such that XY = AB – CD.

**Verification:**On measuring, we observe that XY = 3.9 cm = 7.3 cm – 3.4 cm.

= AB – CD

Thus, XY = AB – CD.

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