**NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1**

NCERT
Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1 are the part of NCERT Solutions for
Class 6 Maths. Here you can find the NCERT Solutions for Class 6 Maths Chapter
14 Practical Geometry Ex 14.1.

**NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.1****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.5****NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.6**

**Ex 14.1 Class 6 Maths Question 1.**

Draw a circle of radius 3.2 cm.**Solution:
**Step 1: Mark a point O as a centre.

Step 2: Open the compass up to the given radius 3.2 cm.

Step 3: Put the pointed edge of the compass at the centre O.

Step 4: Holding the top of the compass, take one full round with pencil. The
figure thus obtained is the required circle of radius 3.2 cm.

**Ex 14.1 Class 6 Maths Question 2.**

With the same centre O, draw two circles of radii 4
cm and 2.5 cm.**Solution:
**Step 1: Mark a point as centre O and open the
compass up to 4 cm.

Step 2: Draw a circle keeping the pointed edge at centre O.

Step 3: Take the same centre O and open the compass up to 2.5 cm, and draw
another circle.

The figure shows the required two circles with the same centre.

**Ex 14.1 Class 6 Maths Question 3.**

Draw a circle and any two of its diameters. If you
join the ends of these diameters, what is the figure obtained? What figure is
obtained if the diameters are perpendicular to each other? How do you check
your answer?**Solution:
**

Step 2: Draw AB and CD two diameters of the circle.

Step 3: By joining the end points of the diameters, we get a quadrilateral ACBD.

Step 4: We note that OA = OB = OC = OD [Same radius]

and AC = DB, AD = BC

∠A = ∠C = ∠B = ∠D = 90°

Thus, ACBD is a rectangle.

Again, if the diameters are perpendicular to each other, then on measuring, we get

AC = AD = DB = BC

Thus, ACBD is a square.

**Ex 14.1 Class 6 Maths Question 4.**

Draw any circle and mark points A, B and C such that(a) A is on the circle.

(b) B is in the interior of the circle.

(c) C is in the exterior of the circle.

**Solution:
**Draw a circle with centre O and any suitable radius.

Here,

(a) A is a point on the circle.

(b) B is a point in the interior of the circle.

(c) C is a point in the exterior of the circle.

**Ex
14.1 Class 6 Maths Question 5.**

Let A, B be the centres of the two circles of equal
radii. Draw them so that each one of them passes through the centre of the
other. Let them intersect at C and D.Examine whether AB and CD are at right angles.

**Solution:
**

In the above figure, two circles of equal radii intersect each other at points C and D. On measuring, we find that AB and CD intersect each other at right angles.

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