**NCERT
Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5**

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry
Ex 10.5 are the part of NCERT Solutions for Class 7 Maths. Here you can find
the NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5.

**NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5**

**Ex 10.5 Class 7 Maths Question 1.**

Construct the right angled ∆PQR, where m∠Q = 90°, QR = 8 cm
and PR = 10 cm.**Solution:**

Steps of construction:

(i) Draw a line segment QR = 8 cm.

Steps of construction:

(ii) Draw ∠Q = 90°.

(iii) With centre R and radius 10 cm, draw an arc to cut the perpendicular line at P.

(iv) ∆PQR is the required triangle.

**Ex 10.5 Class 7 Maths Question 2.**

Construct a right-angled triangle whose hypotenuse
is 6 cm long and one of the legs is 4 cm long.**Solution:**

Steps of construction:

(i) Draw a line segment AB = 4 cm.

Steps of construction:

(ii) Draw ∠A = 90°.

(iii) Cut BC = 6 cm.

(iv) ∆CAB is the required right-angled triangle.

**Ex 10.5 Class 7 Maths Question 3.**

Construct an isosceles right-angled
triangle ABC, where m∠ACB = 90° and AC = 6 cm.**Solution:**

Steps of construction:

(i) Draw a line segment AC = 6 cm.

Steps of construction:

(ii) Draw ∠C = 90°.

(iii) Cut CB = 6 cm.

(iv)
Join AB. Thus, ∆ABC
is the required triangle.

**You can also like these:**

**NCERT Solutions for Maths Class 8**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**

**NCERT Solutions for Maths Class 11**