**NCERT
Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4**

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry
Ex 10.4 are the part of NCERT Solutions for Class 7 Maths. Here you can find
the NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4.

**NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.1****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.4****NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5**

**Ex 10.4 Class 7 Maths Question 1.**

Construct ∆ABC, given m∠A = 60°, m∠B = 30° and AB = 5.8
cm.**Solution:**

Steps of construction:

(i) Draw a line segment AB = 5.8 cm.

Steps of construction:

(ii) Draw ∠A = 60° and ∠B = 30° to meet each other at C.

(iii) ABC is the required triangle.

**Ex 10.4 Class 7 Maths Question 2.**

Construct ∆PQR if PQ = 5 cm, m∠PQR = 105° and m∠QRP = 40°.(Hint: Recall angle-sum property of a triangle)

**Solution:
**Given: m∠PQR = 105°, m∠QRP = 40°

∵ m∠PQR + m∠QRP + ∠QPR = 180° (Angle sum property of a triangle)

105° + 40° + ∠QPR = 180°

145° + ∠QPR = 180°

∴ ∠QPR = 180° – 145° = 35°

**Steps of construction:**

(i) Draw a line segment PQ = 5 cm.

(ii) Draw ∠QPR = 35° and ∠PQR = 40° to meet each other at R.

(iii) ∆PQR is the required triangle. [Using AAS or ASA criterion]

**Ex 10.4 Class 7 Maths Question 3.**

Examine whether you can construct
∆DEF such that EF = 7.2 cm, m∠E = 110° and m∠F = 80°. Justify your answer.**Solution:****
**We cannot construct ∆DEF with the
given measurement.

∵ m∠E + m∠F = 110° + 80°

= 190° > 180° [Sum of the angles of a triangle = 180°]

∴ ∆DEF is not possible to construct.

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