NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4
NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4
are the part of NCERT Solutions for Class 7 Maths. Here you can find the NCERT
Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4.
- NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.1
- NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.2
- NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.3
- NCERT Solutions for Class 7 Maths Chapter 3 Data Handling Ex 3.4
Ex 3.4 Class 7 Maths Question 1.
Tell whether the following situations are certain to happen, impossible to happen, can happen but not certain.(i) You are older today than yesterday.
(ii) A tossed coin will land heads up.
(iii) A dice when tossed shall land up with 8 on top.
(iv) The next traffic light seen will be green.
(v) Tomorrow will be a cloudy day.
Solution:
Event |
Chance |
(i) You are older today than yesterday. |
Certain to happen. |
(ii) A tossed coin will land heads up. |
Can happen but not certain. |
(iii) A dice when tossed shall land up with
8 on the top. |
Impossible to happen. |
(iv) The next traffic light seen will be
green. |
Can happen but not certain. |
(v) Tomorrow will be a cloudy day. |
Can happen but not certain. |
Ex 3.4 Class 7 Maths Question 2.
There are 6 marbles in a box with numbers from 1 to 6 marked on each of them.(i) What is the probability of drawing a marble with number 2?
(ii) What is the probability of drawing a marble with number 5?
Solution:
(i) Total number of marbles marked with the numbers from 1 to 6 = 6
∴ n(S) = 6
Number of marble marked with number 2 = 1
∴ n(E) = 1
∴ Required probability = n(E)/n(S) = 1/6
(ii) Number
of marble marked with number 5 = 1
∴ n(E) = 1
∴ Required probability = n(E)/n(S) = 1/6
Ex 3.4 Class 7 Maths Question 3.
A coin is flipped to decide which team starts the game. What is the probability that your team will start?Solution:
A coin has 2
faces—Head (H) and Tail (T).
∴ Sample space n(S) = 2
Number of
successful event n(E) = 1
∴ Required probability = n(E)/n(S) = ½
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