**NCERT Solutions for Class 11 Maths Chapter 14 Mathematical Reasoning Ex
14.5**

NCERT Solutions for Class
11 Maths Chapter 14
Mathematical Reasoning Ex 14.5 are the part of NCERT Solutions for Class 11
Maths. Here you can find the NCERT Solutions for Class 11 Maths Chapter 14
Mathematical Reasoning Ex 14.5.

**Ex 14.5 Class 11 Maths Question 1.**

Show that the statementp: “If x is a real number such that x

^{3}+ 4x = 0, then x is 0″ is true by

**(i)**direct method,

**(ii)**method of contradiction,

**(iii)**method of contrapositive.

**Solution:**

The given compound statement is of the form “if p then q”

p: x Ïµ R such that x^{3} + 4x = 0

q: x = 0

**(i) Direct method:**

Let us assume that p is true, then

x Ïµ R such that x^{3} + 4x = 0

⇒ x Ïµ R such that x(x^{2} + 4) = 0

⇒ x Ïµ R such that x = 0 or x^{2} + 4 =
0

⇒ x = 0

⇒ q is true.

So, when p is true, q is true.

Thus, the given compound statement is true.

**(ii) Method of contradiction:**

Let us assume that p is true and q is false, then

x Ïµ R such that x^{3} + 4x = 0

⇒ x Ïµ R such that x(x^{2} + 4) = 0

⇒ x Ïµ R such that x = 0 or x^{2} + 4 =
0

⇒ x = 0.

which is a contradiction. So, our assumption that x ≠ 0 is false. Thus, the
given compound statement is true.

**(iii) Method of contrapositive:** Let
us assume that q is false, then x ≠ 0

x Ïµ R such that x^{3} + 4x = 0

⇒ x Ïµ R such that x = 0 or x^{2} + 4 =
0

∴ The statement q is false, so x ≠ 0. So, we have,

x Ïµ R such that x^{2} = -4

Which is not true for any x Ïµ R.

⇒ p is false.

So, when q is false, p is false.

Thus, the given compound statement is true.

**Ex 14.5 Class 11 Maths Question 2.**

Show that the statement “For any real numbers a and b, a^{2}= b

^{2}implies that a = b” is not true by giving a counter-example.

**Solution:**

The given compound statement is of the form “if p then q”

Let us assume that p is true, then a, b Ïµ R such that a^{2} = b^{2}

Let us take a = -3 and b = 3

Now, a^{2} = b^{2}, but a ≠ b

So, when p is true, q is false.

Thus, the given compound statement is not true.

**Ex 14.5 Class 11 Maths Question 3.**

Show that the following statement is true by the method of contrapositive.*p: If x is an integer and x*

^{2}is even, then x is also even.

**Solution:**

The given compound statement is of the form “if p then q”

p: x Ïµ Z and x^{2} is even.

q: x is an even integer.

Let us assume that q is false, then x is not an even integer.

⇒ x is an odd integer.

⇒ x^{2} is an odd integer.

⇒ p is false.

So, when q is false, p is false.

Thus, the given compound statement is true.

**Ex 14.5 Class 11 Maths Question 4.**

By giving a counter example, show that the following statements are not true.**(i)**p: If all the angles of a triangle are equal, then the triangle is an obtuse angled triangle.

**(ii)**q: The equation x

^{2}– 1 = 0 does not have a root lying between 0 and 2.

**Solution:**

**(i)** Since the triangle is an obtuse angled triangle then one angle
measures greater than 90°.

Let one angle = 100°

Also, all the angles of the triangle are equal.

∴ Sum of all angles of the triangle is 300°, which
is not possible.

Thus, the given compound statement is not true.

**(ii)** We see that x = 1 is a root of the equation x^{2} – 1
= 0, which lies between 0 and 2. Thus, the given compound statement is not
true.

**Ex 14.5
Class 11 Maths Question 5.**

Which of the following statements are true and which are false? In each case,
give a valid reason for saying so.**(i)**p: Each radius of a circle is a chord of the circle.

**(ii)**q: The centre of a circle bisects each chord of the circle.

**(iii)**r: Circle is a particular case of an ellipse.

**(iv)**s: If x and y are integers such that x > y, then -x < -y.

**(v)**t: √11 is a rational number.

**Solution:**

**(i)** A chord of a circle is a line whose two endpoints lie on the
circle. So, the radius of a circle is not a chord of the circle. Thus, the
given statement is false.

**(ii)** The centre of a circle bisects chord of circle when the chord
is diameter of circle. When the chord is other than diameter, then the centre
of the circle does not lie on the chord. Thus, the given statement is false.

**(iii)** In the equation of an ellipse if we put a = b, then we get an
equation of a circle.

Thus, the given statement is true.

**(iv)** It is given that x, y Ïµ Z such that x > y. Multiplying both
sides by negative sign, we get x, y Ïµ Z such that -x < -y.

Thus, the given statement is true.

**(v)** Since √11 cannot be
expressed in the form a/b, where a and b are
integers and b ≠ 0. Thus, the given statement is false.

**You can also like these:**

**NCERT Solutions for Maths Class 9**

**NCERT Solutions for Maths Class 10**