**NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4**

NCERT Solutions for Class
11 Maths Chapter 11 Conic
Sections Ex 11.4 are the part of NCERT Solutions for Class 11 Maths. Here you
can find the NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex
11.4.

**In each of the Exercises 1 to 6, find the coordinates of the foci and
the vertices, the eccentricity and the length of the latus rectum of the
hyperbolas.**

**Ex 11.4 Class 11 Maths Question 1.**

x^{2}/16 − y

^{2}/9 = 1

**Solution:**

The given equation of the hyperbola is:

**Ex 11.4 Class 11 Maths Question 2.**

y^{2}/9 − x

^{2}/27 = 1

**Solution:**

The given equation of the hyperbola is:

**Ex 11.4 Class 11
Maths Question 3.**

### 9y^{2} – 4x^{2} = 36

**Solution:**

The given equation of the hyperbola is:

9y^{2} – 4x^{2} = 36

**Ex 11.4 Class 11
Maths Question 4.**

16x^{2}– 9y

^{2}= 576

**Solution:**

The given equation of the hyperbola is:

16x^{2} – 9y^{2} = 576

**Ex 11.4 Class 11 Maths Question
5.**

5y^{2}– 9x

^{2}= 36

**Solution:**

The given equation of the hyperbola is:

5y^{2} –
9x^{2} = 36

**Ex 11.4 Class 11
Maths Question 6.**

49y^{2}– 16x

^{2}= 784

**Solution:**

The given equation of the hyperbola is:

49y^{2} – 16x^{2} = 784

**In each of the Exercises 7 to
15, find the equations of the hyperbola satisfying the given conditions.**

**Ex 11.4 Class 11
Maths Question 7.**

Vertices (±2, 0), foci (±3, 0)

**Solution:**

The vertices are (±2, 0) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 11.4 Class 11 Maths Question
8.**

Vertices (0, ±5), foci (0, ±8)

**Solution:**

The vertices are (0, ±5) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 11.4 Class 11
Maths Question 9.**

Vertices (0, ±3), foci (0, ±5)

**Solution:**

The vertices are (0, ±3) which lie on x-axis. So, the equation of the hyperbola
in standard form is:

**Ex 11.4 Class 11
Maths Question 10.**

Foci (±5, 0), the transverse axis is of length 8.

**Solution:**

Here, the foci are (±5, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 11.4 Class 11
Maths Question 11.**

Foci (0, ±13), the conjugate axis is of length 24.

**Solution:**

Here, the foci are (0, ±13) which lie on y-axis. So, the equation of the
hyperbola in standard form is:

**Ex 11.4 Class 11 Maths Question 12.**

Foci (±3√5, 0), the latus rectum is of length 8.

**Solution: **

Here, the foci are (±3√5, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 11.4 Class 11
Maths Question 13.**

Foci (±4, 0), the latus rectum is of length 12.

**Solution:**

Here, the foci are (±4, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 11.4 Class 11 Maths Question 14.**

Vertices (±7, 0), e = 4/3.

**Solution:**

Here, the vertices are (±7, 0) which lie on x-axis. So, the equation of the
hyperbola in standard form is:

**Ex 11.4 Class 11 Maths Question 15.**

Foci (0, ±√10), passing
through (2, 3).

**Solution: **

Here, the foci are (0, ±√10) which lie on
y-axis. So, the equation of the hyperbola in standard form is:

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